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marusya05 [52]
3 years ago
14

How does the abundance of various isotopes affect the atomic mass?

Chemistry
1 answer:
eduard3 years ago
6 0

solution:

The quoted atomic mass on the Periodic Table is the WEIGHTED average of the individual isotopic masses. The higher the isotopic percentage, the MORE that isotope will contribute to the isotopic mass. For this reason, most masses that are quoted on the Table are non-integral.

By way of example we could look to the hydrogen atom. The VAST majority of hydrogen atoms (in this universe) are the protium isotope. i.e. 1H, whose nuclei contain JUST the defining proton. There is a smaller percentage (>1%) of hydrogen atoms WITH one NEUTRON in their nuclei to give the deuterium isotope. i.e. 2H, and because this is relatively cheap, and easily incorporated into a molecule, deuterium labelling is routinely used in analysis.

And there is even a smaller percentage of hydrogen atoms with TWO NEUTRONS in their nuclei, to give the tritium isotope. i.e. 3H. The weighted average of the isotopic percentages gives 1.00794⋅g⋅mol^{−1}


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Answer:

Most of free energy available from oxidation of the glucose remains in pyruvate.

Explanation:

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Glucose + 2 NAD⁺ + 2 ADP + 2 Pi ⇒ 2 Pyruvate + 2 NADH + 2 H⁺ + 2ATP

Glucose is oxidized to give 2 molecules of pyruvate and 2 molecules of NADH and ATP (Energy currency).

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3 years ago
how many liters of radon gas would be in 3.43 moles at standard temperature and pressure (273K and 100 kPa)?
bagirrra123 [75]

Answer:

V = 0.0007678398L

Explanation:

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Number of moles of gas = 3.43moles

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Unknown:

Volume of gas = ?

Solution

The gas is at standard temperature and pressure, this implies we can use the ideal gas equation to solve for the unknown.

Mathematically, the law is expressed as:

                               PV = nRT

The unknown here is the Volume, V. We know the other parameters.

       P = pressure on the gas

      n = number of moles

       R = gas constant=0.082

       T = temperature

now, we have to make V the subject of the expression:

                   V = \frac{nRT}{P}

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3 years ago
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