Answer:
It's mileage is 5.95 km per liter.
Assuming that the number of mols are constant for both conditions:
Now you plug in the given values. V_1 is the unknown.
Separate V_1
V= 162.782608696 L
There are 2 sig figs
V= 160 L
Answer:
+4
Explanation:
An atom is considered to be neutral before losing or gaining any electrons. They are neutral in charge because they initially have the same number of protons (with charge of +1 each) and electrons (with a charge of -1 each).
Consider charge in an electron like a balance, with positively charged protons on one side and negatively charged electrons on the other. When you have the same number of each, there is equal amounts of positive and negative charge so the atom is neutral with a charge of zero.
For example, potassium has 19 protons, and 19 electrons. This means it has
19 positive charges and 19 negative charges. If you take away one electron, it now has 19 positive charges and 18 negative charges. So there is one more positive charge than negative, which means it is now an ion (a charged atom) with a charge of +1. If you take away two electrons the charge becomes +2... 4 electrons the charge becomes +4.
Answer:
x = 86.908 amu
Explanation:
Average mass of isotope = 85.4678 amu
Rb-85 = 84.9117 amu, Percentage = 72.15% = 0.7215
Other isotope = x, Percentage = 100 - 72.15 = 27.85% = 0.2785
Average mass = (Percentage * Mass of Rb-85) + (Percentage * Mass of Rb-87)
85.4678 = (0.7215 * 84.9117) + (0.2785 * x)
85.4678 = 61.2638 + 0.2785x
0.2785x = 24.204
x = 24.204 / 0.2785
x = 86.908 amu
Aluminum reacts with oxygen based on the following equation:
<span> 4Al + 3O2 → 2Al2O3
From this balanced equation, we can see that 4 moles of aluminum are required to react with 3 moles of oxygen.
So, to find the number of moles of oxygen needed to react with 1.44 moles of aluminum, all you have to do is cross multiplication as follows:
required moles of oxygen = (1.44x3) / 4 = 1.08 moles</span>
