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nikdorinn [45]
2 years ago
6

Que tipo de mistura tem a agua mineral?

Chemistry
1 answer:
QveST [7]2 years ago
6 0

Answer:

mezcla homogénea

El agua en sí es un ejemplo de mezcla homogénea. Todo el agua, excepto la más pura, contiene minerales y gases disueltos. Estos se disuelven en todo el agua, por lo que la mezcla se presenta en la misma fase y es homogénea.

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How does a barometer predict the weather?
Lunna [17]

Answer:

<em>Barometers measure this pressure. ... Changes in the atmosphere, including changes in air pressure, affect the weather. Meteorologists use barometers to predict short-term changes in the weather. A rapid drop in atmospheric pressure means that a low-pressure system is arriving.</em>

Explanation:

<h3><em>I </em><em>hope</em><em> this</em><em> helps</em><em>!</em></h3>
6 0
2 years ago
Consider the formation of nitrogen dioxide from nitric
Temka [501]

Answer:

9 L

Explanation:

According to the question , the given reaction is -

2NO(g) + O₂(g)------->2NO₂(g)

Since ,

At STP ,

One mole of a gas occupies the volume of 22.4 L.

Hence , as given in the question -

9 L of NO , i.e .

22.4 L = 1 mol

1 L = 1 / 22.4 mol

9 L = 1 / 22.4  * 9 L = 0.40 mol

From the chemical reaction ,

The Oxygen is in excess , hence NO becomes the limiting reagent , and will determine the moles of product .

Hence ,  

2 moles of NO will produce 2 moles of NO₂.

Therefore ,

0.40 mol of NO will produce 0.40 mol of NO₂.

Hence , the volume of NO₂ can be calculated as -

1 mol = 22.4 L

0.40 mol = 0.40 * 22.4 L = 9 L

6 0
3 years ago
How many molecules are in 120 grams of Na2SO4
brilliants [131]

3.06 × 10^23 molecules

5 0
3 years ago
A 3.82-g sample of magnesium nitride is reacted with 7.73 g of water. mg3n2 (s) + 3 h2o (â) â 2 nh3 (g) + 3 mgo (s) the yield of
horrorfan [7]
The reaction is properly written as

Mg₃N₂ (s) + 3 H₂O (l) --> 2 NH₃<span> (g) + 3 MgO (s) 

Molar mass of Mg</span>₃N₂ = 100.95 g/mol
Molar mass of H₂O = 18 g/mol
Molar mass of MgO = 40.3 g/mol

Moles Mg₃N₂: 3.82/100.95 = 0.0378
Moles H₂O: 7.73/18 = 0.429 

Theo H₂O required for available Mg₃N₂: 0.0378*3/1 = 0.1134 mol
Hence, the limiting reactant is Mg₃N₂.
Thus,

Theoretical Yield = 0.0378 mol Mg₃N₂ * 3 mol MgO/Mg₃N₂ * 40.3 g/mol
Theo Yield = 4.57 g

Percent Yield = Actual Yield/Theo Yield * 100
Percent Yield = 3.60 g/4.57 g * 100 =<em> 78.77%</em>
5 0
3 years ago
How much energy is released when 0.40 mol C6H6(g) completely reacts with oxygen.
Mashutka [201]
You have to find the gram formula mass of C6H6 then do mass (g) = mol x GFM
5 0
3 years ago
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