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kotegsom [21]
3 years ago
8

How would the gravitational force between the Earth and Moon change if the distance between them was halved?

Physics
1 answer:
motikmotik3 years ago
6 0

Answer:

The gravitational force would be stronger.

Explanation:

Force of gravitation increases by 4 times when distance reduced by half.

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While getting buff at the gym you lift a bunch of weights applying 1000N of force to lift them from the ground to a height of 2m
slega [8]
A. 2000 J............
8 0
3 years ago
When you take pictures with a camera, the distance between the lens and the film or chip has to be adjusted, depending on the di
Shalnov [3]

Answer:

Explanation:

When a camera shifts focus from a faraway object to a nearby object, the lens-to-film distance must increase. Likewise, when it shifts focus from a nearby object to a distant object, there must be an increase in the lens to film distance (that is, the image distance).

Therefore, if the picture of an object that is far away, the lens must move towards the film.

The focal length cannot be changed because it is fixed for a lens. Nevertheless, in order to focus on an object, the image distance can be changed.

8 0
4 years ago
Neutrons incident on a heavy nucleus with spin J 0 show a resonance at an incident energy ER = 250 eV in the total cross-section
ivolga24 [154]

Answer:

elastic partial width is 2.49 eV

Explanation:

given data

ER  E = 250 eV

spin J = 0

cross-section magnitude σ = 1300 barns

peak P = 20ev

to find out

elastic partial width W

solution

we know here that

σ = λ²× W /  ( E × π × P )     ...................1

put here all value

σ = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

1300 × 10^{-24} = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

solve it and we get W

W = 249.56 × 10^{-2}

so elastic partial width is 2.49 eV

8 0
4 years ago
Two bicyclists were riding their bikes at a rate of 20 kilometers per hour (km/h). During the next half hour, they observed that
Ghella [55]

Answer: 4 night’s

Explanation:

3 0
3 years ago
One of Lex Luthor's henchman attacks Superman, shooting a rapid-fire stream of 3.3 g bullets at him at a rate of 112/min. The sp
igor_vitrenko [27]

Answer:

3.2451N

Explanation:

Mass of the bullet (m) = 3.3g = 3.3*10^{-3}Kg

Speed of the bullet (V)= 527m/s

Rate of bullet (r) = 112/min = 1.866\sec

We can calculate with this information the average acceleration of bullets

a=V*r = 527\frac{m}{s}\frac{1.866}{s} = 983.38m/s^2

The force is given by,

F=ma\\F=(3.3*10^{-3})*983.38m/s^2 = 3.2451N

That is just because he is Superman.

4 0
3 years ago
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