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Fynjy0 [20]
3 years ago
12

Help me please :3 :3 :3 ;3

Chemistry
2 answers:
jolli1 [7]3 years ago
7 0
I believe it would be A! -good vibes, and I hope you end up passing this test or homework assignment! (:
inna [77]3 years ago
6 0
A: because the light is lower than the hole, it will come in at in inclined angle. if the hole was say at the same level as the hole, it would shine straight to the other side of the box
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A deficiency in B6 (pyridoxal phosphate) would negatively impact which of the following pathways: 1. Metabolism of homocysteine
Thepotemich [5.8K]

Answer:

The correct answer is 1.

Explanation:

The metabolism of homocysteine produces a sulfur amino acid that is normally formed from methionine during the fulfillment of its function as a donor of methyl groups. Metabolic fate such as remethylation and transsulfuration, involving the enzymatic forms of the vitamins folacin, B12, and B6, gives rise to homocysteine and mixed disulfides including so-called protein-linked homocysteine, the main form circulating in plasma. B6 deficiency would have a direct impact on the metabolism of homocysteine to cysteine.

Have a nice day!

7 0
3 years ago
A bowling ball, a baseball, a tennis ball, and a ping-pong ball are all dropped from a height of 2 meters. Which has the most ki
mr_godi [17]

Answer:

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6 0
3 years ago
Is bleach liquid starch? <br> Yes or No
Jobisdone [24]

Answer:

O it's not

Explanation:

Have a great day!

8 0
3 years ago
Natural remedies are usually more effective and safer because they have thoroughly tested .
mihalych1998 [28]
The answer for this question would be B) False or the second option.

Answer is FALSE: ✅
6 0
3 years ago
You have an aqueous solution of chromium(III) nitrate that you titrate with an aqueous solution of sodium hydroxide. After a cer
barxatty [35]

Answer:

The precipitate was chromium hydroxide, which then reacted with more hydroxide to produce a soluble complex, Cr(OH)4

Explanation:

The following reaction takes place when chromium(III) nitrate reacts with NaOH:

Cr(NO)_{3} +3 NaOH → Cr(OH)_{3} (s)+ NaNO_{3}

The precipitate that is formed is chromium hydroxide, Cr(OH)_{3}

When more NaOH is added, the precipitate reacts with it which then results in the formation of a soluble complex ion:

Cr(OH)_{3}(s) + OH^{-}(aq) → Cr(OH)_{4} ^{-}(aq)

Cr(OH)_{4} ^{-} is soluble complex ion

7 0
4 years ago
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