Answer:
Explanation:
Lisoprisil's molecular mass is 405.488g/mol, we'll use this fact to calculate molarity, which units are mol/L, and we proceed to the calculus:
- First, we'll unify unities, the 10 milligrams of lisinopril we'll transform into grams.
- Now that we have the same unities we'll calculate molarity using the molecular mass, the grams of lisinopril and the liters in which these grams are, let's consider that our final unities have to be mol/L.
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Answer:
a) MZ₂
b) They have the same concentration
c) 4x10⁻⁴ mol/L
Explanation:
a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.
The salts solubilization reactions and their Kps values are:
MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²
MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³
Thus, the Kps of MZ₂ has a larger value.
b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.
c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:
8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.
Neutralization reaction is the reaction between acid and base.
There the neutralization reaction is:
HBr + LiOH ----------> LiBr + H2O.
Hope this helps!
Answer:
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