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WARRIOR [948]
3 years ago
6

Need help please please

Chemistry
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

1) 4

2) 1/9

3) 46.5

4) 5.8

Explanation:

Density= Mass/Volume

1) D=24/6=4

2) D=1/9=0.11

3) D=2000/43=46.5

4) D=75/13=5.8

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If a 750 mL of a gas at a pressure of 100.7 kPa has a decrease of pressure to 99.8 kPa, what is the new volume? Show work
SVEN [57.7K]

Explanation:

P1V1 = P2V2

(100.7 kPa)(0.75 L) = (99.8 kPa)V2

V2 = (100.7 kPa)(0.75 L)/(99.8 kPa)

= 0.757 L

4 0
3 years ago
Weight is measured using an instrument called a
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I believe the answer is a balance or mechanical scale
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A voltaic cell has a zinc anode and a copper cathode. They are connected by a wire but no salt bridge. What can you predict will
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The prediction is that B. The electrons will flow to the zinc anode where a negative charge will build up and eventually halt the reaction.

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Without the salt bridge, positive and negative charges will build up around the electrodes causing the reaction to stop.

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4 0
2 years ago
Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr
VikaD [51]

Answer : The value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

Explanation :

The balanced cell reaction will be,

Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)

The half-cell reactions are:

Oxidation reaction (anode) : Pb(s)\rightarrow Pb^{2+}(aq)+2e^-

Reduction reaction (cathode) : 2Ag^+(aq)+2e^-\rightarrow 2Ag(g)

Relationship between standard Gibbs free energy and standard electrode potential follows:

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where,

\Delta G^o = standard Gibbs free energy

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n = number of electrons in oxidation-reduction reaction = 2

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Now put all the given values in the above formula, we get:

\Delta G^o=-2\times 96500\times 0.93

\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol

Now we have to calculate the value of 'K'.

\Delta G^o=-RT\ln K

where,

\Delta G_^o =  standard Gibbs free energy  = -180 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K

K=3.6\times 10^{31}

Therefore, the value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

5 0
3 years ago
What is the difference between a weak and strong base?
morpeh [17]
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6 0
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