Answer:
8.1107 g
Explanation:
The given reaction:
Given that:
Mass of silver sulfadiazine = 25.0 g
Molar mass of silver sulfadiazine = 357.14 g/mol
The formula for the calculation of moles is shown below:
Thus,
From the reaction,
2 moles of silver sulfadiazine are formed from 1 mole of silver oxide
So,
1 mole of silver sulfadiazine are formed from 1/2 mole of silver oxide
0.07 mole of silver sulfadiazine are formed from 1/2*0.07 mole of silver oxide
Moles of silver oxide = 0.035 moles
Molar mass of silver oxide = 231.735 g/mol
Mass = Moles * Molar mass = 0.035 moles * 231.735 g/mol = 8.1107 g
Carbon is located in the fourth group, second period. It is also in the nonmetal section of the table as well
The answer is: " 56 g CaCl₂ " .
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Explanation:
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2.0 M CaCl₂ = 2.0 mol CaCl₂ / L ;
Since: "M" = "Molarity" (measurement of concentration);
= moles of solute per L {"Liter"} of solution.
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Note the exact conversion: 1000 mL = 1 L .
Given: 250 mL ;
250 mL = ? L ? ;
250 mL * (1 L / 1000 L) = (250/1000) L = 0.25 L .
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(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol = 0.50 mol CaCl₂ ;
We have: 0.50 mol CaCl₂ ; Convert to "g" (grams):
→ 0.50 mol CaCl₂ .
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1 mol CaCl₂ = ? g ?
From the Periodic Table of Elements:
1 mol Ca = 40.08 g
1 mol Cl = <span>35.45 g .
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There are 2 atoms of Cl in " CaCl₂ " ;
→ Note the subscript, "2", in the " Cl₂ " ;
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So, to calculate the molar mass of "CaCl₂" :
40.08 g + 2(35.45 g) =
40.08 g + 70.90 g = 110.98 g ; round to 4 significant figures;
→ round to 111 g/mol .
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So:
→ 0.50 mol CaCl₂ = ? g CaCl₂ ? ;
→ 0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;
= (0.50) * (111 g) CaCl₂ ;
= 55.5 g CaCl₂ ;
→ round to 2 significant figures;
→ 56 g CaCl₂ .
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The answer is: " 56 g CaCl₂ " .
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