Respuesta:
90.0 %
Explicación:
Paso 1: Escribir la ecuación química balanceada
N₂ + 3 H₂ ⇒ 2 NH₃
Paso 2: Calcular el rendimiento teórico de NH₃ a partir de 140 g de N₂
En la ecuación balanceada, participan de N₂: 1 mol × 28.01 g/mol = 28.01 g y de NH₃: 2 mol × 17.03 g/mol = 34.06 g.
140 g N₂ × 34.06 g NH₃ /28.01 g N₂ = 170 g NH₃
Paso 3: Calcular el rendimiento porcentual de NH₃
El rendimiento experimental de NH₃ es 153 g. Podemos calcular el rendimiento porcentual usando la siguiente fórmula.
R% = rendimiento experimental / rendimiento teórico × 100%
R% = 153 g / 170 g × 100% = 90.0 %
1.7960L
Explanation:
the mass of the gas is constant in both instances
pv/T=constant(according to pv=nRT)
745mmHg*2L/298K=760mmHg*v/273K
v=1.7960L
Answer:
Your answer is potASSium Iodide
Explanation:
I took the test yesterday
Please give brainliest
- The mass in kilograms is (11971.98 Kg)
- Pounds can be converted to pounds to kilograms by using this conversation (1 pound = 0.454 kilogram)
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- <em>Let X= mass of the object in kilograms</em>
- <em>(1 pound = 0.454 kilogram)</em>
- 26370 pounds = X kilograms
- <em>If we cross multiply, we have </em>
- (0.454 kilogram × 26370 pounds) = X kilograms
X = 11971.98 Kg
- Therefore, mass in kilograms is (11971.98 Kg)
Learn more at : brainly.com/question/17482095
Answer:
Explanation:
When you are in the laboratory and take a direct sniff of the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When it is necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air toward your face.
