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Elden [556K]
3 years ago
8

Which is a strong base? HCl NaOH NH3 H3CO3

Chemistry
1 answer:
STatiana [176]3 years ago
6 0

Answer:

The answer is B: NaOH :3

Explanation:

Hope this helped :D

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ivanzaharov [21]
Air resistance depends on two important factors - the speed of the object and it's surface area. Increasing the surface area of an object decreases it's speed
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How do social forces shape technology
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Social forces shape technology both in the form of deliberate social activism and also in unconscious ways. For example, in social activism, large demonstrations against oil pipelines can lead to more rapid development of alternatives to fossil fuels. Somewhat unconsciously, the clogging of cars in tight downtown areas in cities and decreasing parking space gave an impetus to develop new forms of rapid transit like subways and electric articulated buses. 




8 0
3 years ago
Which shows the formula for an Organic acid
tresset_1 [31]
Answer:
            The formula of Organic acid is as follow,

                                                 R-COOH

Explanation:
                   The class of organic acids is called Carboxylic Acids. In above general structure, R is alkyl group and can vary. While -COOH is the functional group. 
                    Carboxylic Acids has the tendency to loose protons and their pKa value depends upon the alkyl group. For example the pKa value of Acetic acid (R = -CH₃) is 4.7. The driving force for this acidity is the stability of carboxylate (conjugate base) due resonance. i.e

                               RCOOH     ⇄    RCOO⁻  +  H⁺
Where;
            RCOO⁻  =  Carboxylate Ion (Conjugate base)
3 0
3 years ago
A hydrate of zinc nitrate has the formula Zn(NO3)2 . xH2O. If the mass of 1 mol of anhydrous zinc nitrate is 63.67% of the mass
weqwewe [10]

MM Zn(NO₃)₂ = 189.36 g/mol

mass 1 mol Zn(NO₃)₂ = 189.36 g

mass hydrate = 100 / 63.67 x 189.36 = 297.409 g

mass 1 mol hydrate = 297.409 g

MM hydrate = 297.409 g/mol

MM hydrate = MM Zn(NO₃)₂ + MM xH₂O

297.409 = 189.36 + x(18)

x = 6

6 0
2 years ago
5. A 5.00 g sample of an unknown substance was heated from 25.2 C to 55.1 degrees * C , and it required 133 to do so. Identify t
Leviafan [203]

Answer:

Aluminum

Explanation:

Given

T_1 = 25.2^oC

T_2 = 55.1^oC

m = 5.00g

\triangle Q= 133J

<em>See attachment for chart</em>

Required

Identify the unknown substance

To do this, we simply calculate the specific heat capacity from the given parameters using:

c = \frac{\triangle Q}{m\triangle T}

This gives:

c = \frac{\triangle Q}{m(T_2 - T_1)}

So, we have:

c = \frac{133J}{5.00g * (55.1C - 25.2C)}

c = \frac{133J}{5.00g * 29.9C}

c = \frac{133J}{149.5gC}

c = 0.89\ J/gC

From the attached chart, we have:

Al(s) = 0.89\ J/gC --- The specific heat capacity of Aluminum

<em>Hence, the unknown substance is Aluminum</em>

7 0
3 years ago
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