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Elden [556K]
3 years ago
8

Which is a strong base? HCl NaOH NH3 H3CO3

Chemistry
1 answer:
STatiana [176]3 years ago
6 0

Answer:

The answer is B: NaOH :3

Explanation:

Hope this helped :D

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Consider the hypothetical serine protease, which shows the specificity pockets. The S1 pocket has a glutamic acid in the bottom,
BigorU [14]

Answer:

See explaination

Explanation:

Hydrophobic literally means “the fear of water”. Hydrophobic molecules and surfaces repel water. Hydrophobic liquids, such as oil, will separate from water. Hydrophobic molecules are usually nonpolar, meaning the atoms that make the molecule do not produce a static electric field.

Please see attachment for the step by step solution of the given problem.

8 0
3 years ago
Explain how you determine the freezing point of a solution that does not have a well-defined transition in the cooling curve.
Sophie [7]

This question is asking for a method for the determination of the freezing point in a solution that does not have a noticeable transition in the cooling curve, which is basically based on a linear fit method.

The first step, would be to understand that when the transition is well-defined as the one on the attached file, we can just identify the temperature by just reading the value on the graph, at the time the slope has a pronounced change. For instance, on the attached, the transition occurs after about 43 seconds and the freezing point will be about 4 °C.

However, when we cannot identify a pronounced change in the slope, it will be necessary to use a linear fit method (such as minimum squares) to figure out the equation for each segmented line having a significantly different slope and then equal them so that we can numerically solve for the intercept.

As an example, imagine two of the segmented lines have the following equations after applying the linear fit method:

y=-3.5 x + 25\\\\y=-0.52 x + 2

First of all, we equal them to find the x-value, in this case the time at which the freezing point takes place:

-3.5 x + 25=-0.52 x + 2\\\\-3.5 x+0.52 x =2-25\\\\x=\frac{-23}{-2.98}=7.72

Next, we plug it in in any of the trendlines to obtain the freezing point as the y-value:

y=-3.5 (7.72) + 25\\\\y = 1.84

This means the freezing point takes place after 7.72 second of cooling and is about 1.84 °C. Now you can replicate it for any not well-defined cooling curve.

Learn more:

  • brainly.com/question/22818252
  • brainly.com/question/9680530

7 0
3 years ago
A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20
notsponge [240]

P1 * V1 ÷ T1 = P2 * V2 ÷ T2  

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420  

30,144 * V2 = 22,680  

V2 = 22,680 ÷ 30,144  

The new volume is approximately 0.75 liter.

I hope I helped

5 0
3 years ago
Read 2 more answers
Which best describes a molecule?
lesantik [10]
I think it is the third statement
‘A unit is made up of two or more atoms’
3 0
3 years ago
Read 2 more answers
An atom of uranium-238 undergoes radioactive decay to form an atom of thorium-234. Which type of nuclear decay has occurred?
WINSTONCH [101]

Answer:-

Alpha decay

Explanation:-

Uranium 238 has atomic number 92 and mass number 238.

Thorium 234 has atomic number 90 and mass number 234.

So, the change in atomic number as uranium 238 disintegrates into thorium234 = 92 – 90 = 2

So, the change in mass number as uranium 238 disintegrates into thorium234= 238 – 234 = 4

We know that when an alpha particle is emitted, the mass number decreases by 4 and the atomic number decreases by 2.

So when an atom of uranium 238 undergoes radioactive decay to form an atom of thorium-234, alpha decay has occurred.

5 0
3 years ago
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