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mart [117]
3 years ago
8

For this PreLab assignment we will assume all of the acid is the monoprotic acid acetylsalicylic acid (C9H8O4). [Note: for your

analysis in the PostLab you will subtract the moles of salicylic acid from the total acid content to determine the amount of acetylsalicylic acid]. How many moles of acetylsalicylic acid are in the 0.2001 g sample of your aspirin
Chemistry
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

0.0011 moles

Explanation:

Recall that;

Number of moles = mass of substance/ molar mass of the substance

Mass of asprin = 0.2001 g

Molar mass of asprin = 180.158 g/mol

Number of moles =  0.2001 g/180.158 g/mol

Number of moles = 0.0011 moles

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Answer:- 27.7 grams of PbI_2 are produced.

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let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

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= 27.7gPbI_2

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