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navik [9.2K]
3 years ago
7

Electricity is generated in two forms namely………A. Alternating current and wave form B. Alternating current and basic current C.

Alternating current and direct current D. Direct current and indirect current E. Direct current and simple current 20. Which of the following liquid substance is used in electrolysis? A. fluid B. Flux C. Solder D. Solute E. Electrolyte pleaseee heeeelp
Engineering
2 answers:
Eva8 [605]3 years ago
5 0

Answer:

The correct options are;

C. Alternating current and direct current

E. Electrolyte

Explanation:

Electricity is generated in either AC or DC depending on the source of the energy which aids the electricity generation;

The most common method through which electricity is generated and through which the principle of electric generation was discovered by Michael Faraday, is the rotation of a wire loop or coil between the North and South poles of a magnet to produce Alternating Current

Electricity is also generated in Direct Current by solar cells which convert sunlight into electric energy by photovoltaic effect.

20. Electrolysis is a chemical reaction that is brought about by the application or passing of a direct electric current through an electrolyte, which is an ion containing liquid.

natulia [17]3 years ago
4 0
C and E

Hope this helps
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Why is it that dislocations play an important role in controlling the mechanical properties of metallic materials, however, they
klio [65]

Answer:

dislocations play an important role in controlling as

Explanation:

As dislocations plays an important role in the ductility, elasticity and plurality of materials

  • The elastic and elastic deflections play a large role in their properties as the metallic materials, because the dislocation of a glass material does not play a major role in their properties.

5 0
3 years ago
A smooth sphere with a diameter of 6 inches and a density of 493 lbm/ft^3 falls at terminal speed through sea water (S.G.=1.0027
Pachacha [2.7K]

Given:

diameter of sphere, d = 6 inches

radius of sphere, r = \frac{d}{2} = 3 inches

density,  \rho} = 493 lbm/ ft^{3}

S.G = 1.0027

g = 9.8 m/ m^{2} = 386.22 inch/ s^{2}

Solution:

Using the formula for terminal velocity,

v_{T} = \sqrt{\frac{2V\rho  g}{A \rho C_{d}}}              (1)

(Since, m = V\times \rho)

where,

V = volume of sphere

C_{d} = drag coefficient

Now,

Surface area of sphere, A = 4\pi r^{2}

Volume of sphere, V = \frac{4}{3} \pi r^{3}

Using the above formulae in eqn (1):

v_{T} = \sqrt{\frac{2\times \frac{4}{3} \pir^{3}\rho  g}{4\pi r^{2} \rho C_{d}}}

v_{T} = \sqrt{\frac{2gr}{3C_{d}}}  

v_{T} = \sqrt{\frac{2\times 386.22\times 3}{3C_{d}}}

Therefore, terminal velcity is given by:

v_{T} = \frac{27.79}{\sqrt{C_d}} inch/sec

3 0
3 years ago
HELP HELP HELP
Fantom [35]

Summary

Students learn about the variety of materials used by engineers in the design and construction of modern bridges. They also find out about the material properties important to bridge construction and consider the advantages and disadvantages of steel and concrete as common bridge-building materials to handle compressive and tensile forces.

This engineering curriculum aligns to Next Generation Science Standards (NGSS).

Engineering Connection

When designing structures such as bridges, engineers carefully choose the materials by anticipating the forces the materials (the structural components) are expected to experience during their lifetimes. Usually, ductile materials such as steel, aluminum and other metals are used for components that experience tensile loads. Brittle materials such as concrete, ceramics and glass are used for components that experience compressive loads.

Learning Objectives

After this lesson, students should be able to:

List several common materials used the design and construction of structures.

Describe several factors that engineers consider when selecting materials for the design of a bridge.

Explain the advantages and disadvantages of common materials used in engineering structures (steel and concrete).

Educational Standards

NGSS: Next Generation Science Standards - Science

Common Core State Standards - Math

International Technology and Engineering Educators Association - Technology

State Standards

Suggest an alignment not listed above

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Worksheets and Attachments

Strength of Materials Worksheet (doc)

Strength of Materials Worksheet (pdf)

Strength of Materials Worksheet Answers (doc)

Strength of Materials Worksheet Answers (pdf)

Strength of Materials Math Worksheet (doc)

Strength of Materials Math Worksheet (pdf)

Strength of Materials Math Worksheet Answers (doc)

Strength of Materials Math Worksheet Answers (pdf)

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MIDDLE SCHOOL Activity

Breaking the Mold

Explanation:

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8 0
2 years ago
A patient has swollen feet, ankles, and legs, and has pain in his lower back. Tests show the level of urea, a waste product, in
myrzilka [38]

Answer: B  Excretory

Explanation: Hope this helps :)

3 0
3 years ago
The time to failure for a gasket follows the Weibull distribution with ß = 2.0 and a characteristic life of 300 days. What is th
Aleks04 [339]

Answer:

64.11% for 200 days.

t=67.74 days for R=95%.

t=97.2 days for R=90%.

Explanation:

Given that

β=2

Characteristics life(scale parameter α)=300 days

We know that Reliability function for Weibull distribution is given as follows

R(t)=e^{-\left(\dfrac{t}{\alpha}\right)^\beta}

Given that t= 200 days

R(200)=e^{-\left(\dfrac{200}{300}\right)^2}

R(200)=0.6411

So the reliability at 200 days 64.11%.

When R=95 %

0.95=e^{-\left(\dfrac{t}{300}\right)^2}

by solving above equation t=67.74 days

When R=90 %

0.90=e^{-\left(\dfrac{t}{300}\right)^2}

by solving above equation t=97.2 days

7 0
3 years ago
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