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stepan [7]
4 years ago
12

A coal-burning power plant generates electrical power at a rate of 650 megawatts (MW), or 6.50 × 108 J/s. The plant has an overa

ll efficiency of 38% for the conversion of heat to electricity. Given this efficiency, how much heat energy in joules is produced in one year of operation??
Engineering
1 answer:
Vinvika [58]4 years ago
7 0

Answer:

Energy produce in one year =20.49 x 10¹⁶ J/year

Explanation:

Given that

Plant produce 6.50 × 10⁸ J/s of energy.

It produce  6.50 × 10⁸ J in 1 s.

We know that

1 year = 365 days

1 days = 24 hr

1 hr = 3600 s

1 year = 365 x 24 x 3600 s

1 year = 31536000 s

So energy produce in 1 year = 31536000 x  6.50 × 10⁸ J/year

          Energy produce in one year = 204984 x 10¹² J/year

          Energy produce in one year =20.49 x 10¹⁶ J/year

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5 0
3 years ago
the increase of current when 15 V is applied to 10000ohm rheostat which is adjusted to 1000ohm value​
Anastasy [175]
Given data:
•) applied voltage = 15 V
•). Resistance = 1000 ohm

Required:
•). The magnitude of current= ?

•••••••••••••SOLUTION•••••••••••••

We can find the relation ship between current, voltage and resistance with the help of Ohms law.

According to ohms law;

V= IR.

Rearranging the above equation;

I= V/ R

Putt the values in the above equation; we get

I= 15V/ 1000ohm

I = 0.015 A( ampere)

••••••••••••••• CONCLUSION•••••••

The value of the current would be 0.15 ampere when Resistance is equal to 1000 and that of Voltage is equal to 15 V.
4 0
3 years ago
Design a plate and frame heat exchanger for the following problem:
qwelly [4]

Answer:

See explaination and attachment.

Explanation:

Iteration method is a repetitive method applied until the desired result is achieved.

Let the given equation be f(x) = 0 and the value of x to be determined. By using the Iteration method you can find the roots of the equation. To find the root of the equation first we have to write equation like below

x = pi(x)

Let x=x0 be an initial approximation of the required root α then the first approximation x1 is given by x1 = pi(x0).

Similarly for second, thrid and so on. approximation

x2 = pi(x1)

x3 = pi(x2)

x4 = pi(x3)

xn = pi(xn-1).

please go to attachment for the step by step solution.

8 0
3 years ago
A 10MHz clock frequency is applied to a cascaded counter consisting of a modulus-5 counter, a modulus-8 counter and two modulus-
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If a clock frequency is applied to a cascaded counter, The lowest output frequency available will be

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<h3>Cascade Counter</h3>

For a cascade counter,

Overall frequency = 5*8*10*10

Overall frequency = 4000

<h3>Lowest Frequency</h3>

Therefore,

the lowest frequency

F = \frac{10*10^6}{4*10^3}\\\\F = 2500Hz\\\\F = 2.5kHz

For more information on frequency, visit

brainly.com/question/17029587?referrer=searchResults

4 0
2 years ago
Which two word pairs to locate the word vicious in the dictionary
Harman [31]

AnsweR Viciously comes from the adjective vicious, which originally meant "of the nature of vice, or wicked." The Latin root, vitiosus, means "faulty, defective, or corrupt."

Explanation:

5 0
3 years ago
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