1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erma4kov [3.2K]
3 years ago
14

Atmospheric pressure decreases as we go higher up the earth's surface. give reasons

Physics
1 answer:
julsineya [31]3 years ago
6 0
Atmospheric pressure is molecular's heavy. So the total number of molecules decreases by going up the surface of the earth. Ok?
You might be interested in
An object has rotational inertia I. The object,initially at rest, begins to rotate with a constant angularacceleration of magnit
Tresset [83]

Answer:

L = I α t

Explanation:

given,                                          

rotational inertia = I              

initial velocity = ω₀                      

magnitude of acceleration = α      

angular momentum = L          

time = t                              

angular acceleration                                

\alpha = \dfrac{\omega-\omega_0}{t}

\alpha = \dfrac{\omega - 0}{t}

\alpha = \dfrac{\omega}{t}

ω = α t..............(1)

angular momentum                    

L = I ω                    

putting value from equation (1)

L = I α t                          

4 0
3 years ago
Can you make the work output of a machine greater than the work input?
drek231 [11]
Nearly equal the output work is greater than the input work because of friction.All machines use some amount of input work to overcome friction.The only way to increase the work output is to increase the work you put into the machine.You cannot get more work out of a machine than you put into it.
4 0
3 years ago
A 45 N girl sits on a bench 0.6 meters off the ground. How much work is done on the bench?
ycow [4]

Answer: 27 joules

Explanation:

Work is done when force is applied on the bench over a distance. it is measured in joules.

Workdone = force x distance

= 45 N x 0.6 metres

= 27 joules

Thus, 27 joules of work is done on the bench.

6 0
4 years ago
Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. Ho
77julia77 [94]

Answer:

The time constant is 1.049.

Explanation:

Given that,

Charge q{t}= 0.65 q_{0}

We need to calculate the time constant

Using expression for charging in a RC circuit

q(t)=q_{0}[1-e^{-(\dfrac{t}{RC})}]

Where, \dfrac{t}{RC} = time constant

Put the value into the formula

0.65q_{0}=q_{0}[1-e^{-(\dfrac{t}{RC})}]

1-e^{-(\dfrac{t}{RC})}=0.65

e^{-(\dfrac{t}{RC})}=0.35

-\dfrac{t}{RC}=ln (0.35)

-\dfrac{t}{RC}=-1.049

\dfrac{t}{RC}=1.049

Hence, The time constant is 1.049.

6 0
3 years ago
Can someone help me asap this is due at 2 50
Rom4ik [11]
The data is inadequate
8 0
3 years ago
Other questions:
  • Tiana jogs 1.5 km along a straight path and then turns and jogs 2.4 km in the opposite direction. She then turns back and jogs 0
    11·1 answer
  • Which of the following statements best states Newton's second law?
    12·1 answer
  • A 0.157-kg baseball moving at 21.2 m/s strikes the glove of a catcher. The glove recoils a distance of 10.7 cm.The magnitude of
    13·2 answers
  • A particle (mass = 4.0 g, charge = 80 mC) moves in a region of space where the electric field is uniform and is given by Ex = -2
    11·1 answer
  • shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const
    5·1 answer
  • A grasshopper jumps and accelerates at 4.5 m/s2. If its legs exert a force of 0.062 N during the jump, what is the mass of the g
    15·1 answer
  • Formula for calculating work done in machines ​
    13·1 answer
  • I need help with one through six please
    6·1 answer
  • Please help me plsss!​
    11·1 answer
  • What do borrowers use to secure a mortgage loan? Check all that apply.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!