Answer:
True
Explanation:
Step 1: Find molecular formula of sucrose
C₁₂H₂₂O₁₁
Step 2: Convert moles of oxygen present to grams
1 mol O = 16 g O
11 mol O = 176 g O
Step 3: Find molar mass of sucrose
C - 12.01 g/mol
H - 1.01 g/mol
O - 16.00 g/mol
12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁
Step 4: Set up dimensional analysis

Step 5: Multiply/Divide and cancel out units
Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.
We are left with grams Oxygen
176/342.34 = 0.514109 grams Oxygen
Answer:
Molecular Formula : NaNO2 or NNaO2 and Molecular Weight:
68.995 g/mol
Explanation:
Answer: The
of a solution is
M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in ml
moles of
= 
Now put all the given values in the formula of molality, we get

pH or pOH is the measure of acidity or alkalinity of a solution.

According to stoichiometry,
1 mole of
gives 1 mole of
Thus
moles of
gives =
moles of
Putting in the values:
![[H^+][OH^-]=10^{-14}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D)
![[0.01][OH^-]=10^{-14}](https://tex.z-dn.net/?f=%5B0.01%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D)
![[OH^-]=10^{-12}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-12%7D)
Thus the
of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 ml of solution is
M
Answer: Option (D) is the correct answer.
Explanation:
A polymer is a large molecule which contains repeating units.
A polymer forms long chain of atoms which are not necessarily arranged in a ring structure. There are not only double bonds between all the carbon atoms, as there can be single bonds or triple bonds between the atoms of a polymer.
A polymer does not contain many different type of molecules as there are many repeating units and not many molecules in a polymer.
A polymer is made of large molecules with repeating units.
Thus, we can conclude that option (D) is the correct answer.