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3 years ago

5

What is the element with period 2 group 14

2 answers:

Ghella [55]3 years ago

7 0

Answer:

Carbon

Explanation:

bija089 [108]3 years ago

6 0

The element name is carbon

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Please answer in order the squares are numbered

insens350 [35]

Answer:

1 , 2 , 3 , 4 , 5

Explanation:

4 0

3 years ago

When the methyl ester of hexanoic acid is hydrolyzed in aqueous sodium hydroxide in the presence of heat, a homogeneous solution

Dovator [93]

Answer:

Hexanoic acid is formed as insoluble product

Explanation:

In aqueous sodium hydroxide, methyl ester of hexanoic acid hydrolyzes to produce soluble sodium hexanoate salt.
Upon addition of aqueous HCl, hexanoate ion is protonated to produce hexanoic acid which is insoluble in water.
Hence, upon acidification of hydrolysis solution, two separate layers (organic and aqueous) are formed.
Reaction are shown below.

4 0

3 years ago

The metric equivalent to 2 tbsp (please show work)

Natasha_Volkova [10]

Answer:

<h2>30 mL</h2>

Explanation:

1tbsp= 15ml

1tbsp+1tbsp=30ml

1+1=2

2x15=30

I hope this helps

4 0

3 years ago

When the color changes is it a chemical change or a physical change

aev [14]

physical

It can be chemical but it's usually physical as the molecular structure doesn't change

5 0

2 years ago

What is the solubility (in g/L) of calcium fluoride at 25°C? The solubility product constant for calcium fluoride is 3.4 × 10–11

PilotLPTM [1.2K]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

$CaF_2\rightleftharpoons Ca^{2+}+2F^-$

s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ca^{2+}][F^-]^2$

We are given:

$K_{sp}=3.4\times 10^{-11}$

Putting values in above equation, we get:

$3.4\times 10^{-11}=(s)\times (2s)^2\\\\3.4\times 10^{-11}=4s^3\\\\s=2.04\times 10^{-4}mol/L$

To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:

Molar mass of calcium fluoride = 78 g/mol

Multiplying the solubility product, we get:

$s=2.04\times 10^{-4}mol/L\times 78g/mol=159.12\times 10^{-4}g/L=0.015g/L$

Hence, the correct answer is Option b.

3 0

3 years ago