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Vlad1618 [11]
3 years ago
11

2 Jim keeps a can on the ramp. The can

Physics
1 answer:
IceJOKER [234]3 years ago
6 0

Answer:

The description of the statement is summarized throughout the explanation section below.

Explanation:

  • The layer of the ramp must've been harsh, which exacerbated the toy movement to occur gradually. This same friction force was indeed starting to function on the remote control car as well as trying to stop that one to react quickly.
  • Jim does have to simplify the exterior including its ramp by scrubbing or greasing to overcome impact as well as make driving travel quicker.

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An 92-kg football player traveling 5.0m/s in stopped in 10s by a tackler. What is the original kinetic energy of the player? Exp
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Explanation:

It is given that,

Mass of the football player, m = 92 kg

Velocity of player, v = 5 m/s

Time taken, t = 10 s

(1) We need to find the original kinetic energy of the player. It is given by :

k=\dfrac{1}{2}mv^2

k=\dfrac{1}{2}\times (92\ kg)\times (5\ m/s)^2

k = 1150  J

In two significant figure, k=1.2\times 10^3\ J

(2) We know that work done is equal to the change in kinetic energy. Work done per unit time is called power of the player. We need to find the average power required to stop him. So, his final velocity v = 0

i.e. P=\dfrac{W}{t}=\dfrac{\Delta K}{t}

P=\dfrac{\dfrac{1}{2}\times (92\ kg)\times (5\ m/s)^2}{10\ s}

P = 115 watts

In two significant figures, P=1.2\times 10^2\ Watts

Hence, this is the required solution.  

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The charges Q1=Q and Q2=4Q that are a distance d apart, repel each other with a force of 1.60 N. What would be the force between
gladu [14]

Answer:

50.4 N

Explanation:

Q1 = Q

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The force is given by

F = \frac{KQ_{1}Q_{2}}{d^{2}}

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F' = \frac{9KQ_{3}Q_{4}}{d^{2}}

F' = \frac{126KQ^{2}}{d^{2}}   .... (2)

Divide equation (2) by equation (1), we get

F' / 1.60 = 126 / 4

F' = 50.4 N

Thus, the force is 50.4 N.

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Answer: The correct answer is graph A.

Explanation:

See Khan Academy.

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