1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Karo-lina-s [1.5K]
3 years ago
7

Psychological profiling is also known as criminal profiling. True or False?

Physics
2 answers:
Nikolay [14]3 years ago
8 0
So my opinion that is false bc. the psychological profiling not is necessary being as criminal profiling ,the criminal mean a greater,intensive word in the way of ,,killer" ,when the ,,psychological" profile is total different way 

hope helped 
Kryger [21]3 years ago
6 0
<span> true, psychological profiling is also known as criminal profiling </span>
You might be interested in
2. What current flows through a hair dryer plugged into a 110 Volt circuit et it as a te
JulsSmile [24]

Explanation:

V =I*R

I= V/I

I=110/25

I= 4.4 Amps

8 0
3 years ago
A sailboat is traveling across the ocean with a speed of 4 m/s when large gusts of wind pick up that starts to accelerate the sa
MatroZZZ [7]
Initial velocity, u = 4 m/s

acceleration due to gusts of wind = 3 m/s^2

time, t = 1 min = 60 s

Let distance travelled = S

From equation of motion,

S = ut +  \frac{1}{2} a {t}^{2}  \\  \\ S = 4 \times 60 +   \frac{1}{2}  \times 3 \times  {60}^{2}  \\  \\ S = 240 + 5400 \\  \\ S = 5640 \: m

Thus, the boat would have traveled 5640m after gusts picked up.
4 0
3 years ago
Read 2 more answers
Having difficulty finding the PE and KE for these values no mass is given. Does anyone know to go solve these?
Alexandra [31]

11) 1.04\cdot 10^7 J

12) 1.04\cdot 10^7 J

13) 50.0 m/s

14) 41.6 m/s

Explanation:

11)

The potential energy of an object is the energy possessed by the object due to its position relative to the ground. It is given by

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity

h is the height relative to the ground

Here in this problem, when the train is at the top, we have:

m = 8325 kg (mass of the train + riders)

g=9.8 m/s^2 (acceleration due to gravity)

h = 127 m (height of the train at the top)

Substituting,

PE=(8325)(9.8)(127)=1.04\cdot 10^7 J

12)

According to the law of conservation of energy, the total mechanical energy of the train must be conserved (in absence of friction). So we can write:

KE_t + PE_t = KE_b + PE_b

where

KE_t is the kinetic energy at the top

PE_t is the potential energy at the top

KE_b is the kinetic energy at the bottom

PE_b is the potential energy at the bottom

The kinetic energy is the energy due to motion; since the train is at rest at the top, we have

KE_t=0

Also, at the bottom the height is zero, so the potential energy is zero

PE_b=0

Therefore, we find:

KE_b=PE_t=1.04\cdot 10^7 J

13)

The kinetic energy of an object is the energy of the object due to its motion. Mathematically, it is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the object

v is the speed of the object

From question 12), we know that the kinetic energy of the train at the bottom is

KE=1.04\cdot 10^7 J

We also know that the mass is

m = 8325 kg

Therefore, we can calculate the speed of the train at the bottom:

v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2(1.04\cdot 10^7)}{8325}}=50.0 m/s

14)

At the top of the second hill, the total mechanical energy of the train is still conserved.

Therefore, we can write again:

KE_1 + PE_1 = KE_2 + PE_2

where

KE_1 is the kinetic energy at the top of the 1st hill

PE_1 is the potential energy at the top of the 1st hill

KE_2 is the kinetic energy at the top of the 2nd hill

PE_2 is the potential energy at the top of the 2nd hill

From the previous questions, we know that

KE_1=0

and

PE_1=1.04\cdot 10^7 J

The height of the second hill is

h = 39 m

So we can also find the potential energy at the second hill:

PE_2=mgh=(8325)(9.8)(39)=3.2\cdot 10^6 J

So, the kinetic energy at the second hill is

KE_2=PE_1-PE_2=1.04\cdot 10^7 - 3.2\cdot 10^6 =7.2\cdot 10^6 J

And so, the speed is

v=\sqrt{\frac{2KE_2}{m}}=\sqrt{\frac{2(7.2\cdot 10^6)}{8325}}=41.6 m/s

4 0
3 years ago
As an interstellar cloud of hydrogen gas shrinks in size, its rate of rotation
FinnZ [79.3K]

Answer:

INCREASES, BECAUSE ITS ANGULAR MOMENTUM IS CONSERVED.

Explanation: Interstellar cloud of Hydrogen is an accumulation of Hydrogen gas in the cloud.

As the Interstellar cloud of Hydrogen shrinks (reduces) in size,the rate of rotation of the shrinked Interstellar cloud Increases because its angular momentum is conserved. GASEOUS MOLECULES MAKE UP ABOUT 99% OF THE INTERSTELLAR CLOUD WITH HYDROGEN HAVING ABOUT 90% OF THE VOLUME OF GASES IN THE INTERSTELLAR CLOUD.

4 0
3 years ago
When sunlight strikes the side of a building, what form of energy is it<br> transformed to?
algol [13]

Answer:

thermal energy

Explanation:

8 0
3 years ago
Other questions:
  • The velocity component with which a projectile covers certain horizontal distance is maximum at the moment of? a) Hitting the gr
    15·1 answer
  • A measure of your memory in which you need to pick the correctly learned answer from a displayed list of options is known as a m
    9·2 answers
  • A boat travels with a velocity equal to 14.0 meters per second, east in 6.15 seconds. What distance in meters does the boat trav
    12·1 answer
  • Is energy absorbed or given off when an electron and a hole of a semi-conductor crystal
    6·1 answer
  • What role did gravity played in the formation of the solar system​
    5·1 answer
  • The tomato is dropped. What is the velocity, v, of the tomato when it hits the ground? Assume 85.6 % of the work done in Part A
    15·2 answers
  • Psychophysic is the study of
    13·2 answers
  • A measure of the average kinetic energy per particle in a quantity of matter
    5·1 answer
  • Question 3
    12·1 answer
  • A 1994 Ford Mustang is driving down a road with a constant speed of 30 31/5, The engine must
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!