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Bumek [7]
2 years ago
14

Which statement is true in comparison to a weak acid, a strong acid

Chemistry
1 answer:
Allushta [10]2 years ago
7 0

Answer: Strong acid vs weak acid

Strong acids and strong bases refer to species that completely dissociate to form ions in solution.

Explanation: By contrast, weak acids and bases ionize only partially, and the ionization reaction is reversible. Thus, weak acid and base solutions contain multiple charged and uncharged species in dynamic equilibrium.

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Deffense [45]

Answer:

2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)  

Explanation:

A thermochemical equation must show the formation of 1 mol of a substance from its elements in their most stable state,.

The only equation that meets those conditions is the last one.

A and B are wrong , because they show Li₂SO₄ as a reactant, not a product.

C is wrong because Li⁺ and SO₄²⁻ are not elements.

D is wrong because it shows the formation of 8 mol of Li₂SO₄.

8 0
2 years ago
The highly reactive elements in group 7a are known for forming salts.what are they called
yaroslaw [1]
Group 7A are halogens 

If you look at a periodic table, these elements include F, Cl, Br, I, and At. Some well known salts are KCl and NaCl (better known as table salt!)
7 0
2 years ago
2.3.12mL =<br> L*<br> O<br> a. .312<br> O b.31.2<br> O<br> C..00312<br> O d..0312
Anna11 [10]

Answer:

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6 0
3 years ago
Consider the following reaction at equilibrium. What effect will decreasing the temperature have on the system? DH=+890kJCO2(g)+
AlladinOne [14]

Answer:

Option B. The reaction will shift to the left in the direction of the reactants.

Explanation:

The equation for the reaction is given below:

CO₂ + 2H₂O <=> CH₄ + O₂

Enthalpy change (ΔH) = +890 KJ

The reaction illustrated by the equation is endothermic reaction since the enthalpy change (ΔH) is positive.

Increasing the temperature of an endothermic reaction will shift the equilibrium position to the right and decrease the temperature will shift the equilibrium position to the left.

Therefore, decreasing the temperature of the system illustrated by the equation above, will shift the reaction to the left in the direction of the reactants.

Thus, option B gives the right answer to the question.

3 0
2 years ago
Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Lo
Fiesta28 [93]

The complete question is: Match the following; Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Long-range interactionsC. Non-covalent interaction formed primarily on the interior of water-soluble proteins.Hydrophobic coreD. Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.

The answer

Disulfide Bonds (Covalent interactions not found in all proteins.)

Peptide Bonds (Covalent interactions found in all proteins.)

Long-range interactions (Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.)

Hydrophobic core. (Non-covalent interaction formed primarily on the interior of water-soluble proteins.)

Explanation:

The phrases have been given the right meaning enclosed in a parentheses. The should be matched accordingly as presented.

5 0
3 years ago
Read 2 more answers
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