Answer:
3.90 L
Explanation:
The reaction between NH₄I and Pb(NO₃)₂ is a double replacement reaction, so, the ions will dissociate and change in the two substances. The ions are NH₄⁺, I⁻, Pb⁺², and NO₃⁻, so the reaction is:
2NH₄I + Pb(NO₃)₂ → PbI₂ + 2NH₄NO₃
Thus, by the stoichiometry of the reactions, 2 moles of NH₄I are necessary to react with 1 mol of Pb(NO₃)₂. According to Proust's law, the proportion of the reaction must be kept so:
2 moles/1 mol = n NH₄I/n Pb(NO₃)₂
The number of moles of Pb(NO₃)₂ that will react is the concentration multiplied by the volume in L, so:
n Pb(NO₃)₂ = 0.280 * 0.905 = 0.2534 mol
2/1 = n NH₄I/0.2534
n NH₄I = 0.5068 mol
The volume of NH₄I is:
n NH₄I = 0.130 *V
0.5068 = 0.130V
V = 3.90 L
