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timurjin [86]
3 years ago
8

Write the expression for the equilibrium constant Keq for the reaction below: 2CO(g) + O2(g) ⇔ 2CO2(g) a. [CO2] / [CO] [O2] b. [

CO]2 / [CO2]2 [O2] c. [CO2]2 / [CO]2 [O2] d. [CO]2 [O2] / [CO2]2 Group of answer choices
Chemistry
1 answer:
kodGreya [7K]3 years ago
5 0

Answer: The answer is NOT A. [CO2] / [CO] [O2]

just took the test and I chose A. The test did not tell me the correct answer. Sorry.

Explanation: NOT, I REPEAT NOT: A. [CO2] / [CO] [O2]

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The proprietor of a rock shop insists that a nugget is pure gold. if the nugget occupies a volume of 5.40 ml, what would its mas
statuscvo [17]

Density of gold = 19.3 g/mL

Density can be calculated from volume and mass of a substance as follows,

Density = \frac{Mass}{Volume}

Given the volume of gold nugget = 5.40 mL

Calculating the mass of gold nugget from density and volume:

Density = \frac{Mass}{Volume}

Mass = Density * Volume

5.40 mL * 19.3 \frac{g}{mL} =104.22 g

Therefore, the mass of the nugget is 104.22 g

7 0
3 years ago
Whats the complete chemical symbol for the ion that has : 13 neutrons 11 protons , and 9 electrons.
myrzilka [38]
The answer gonna be Na2+
7 0
3 years ago
Can someone help me with these two questions?
guapka [62]

Answer:

no

Explanation:

I can't help

5 0
3 years ago
Plz help!!!!!!
Sever21 [200]

this shows that magnesium is higher in the reactivity series than lead.

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5 0
3 years ago
If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered un
Murrr4er [49]

Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Explanation:

A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{36 g}{58.4 g/mol}\\= 0.616 mol

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.

So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

  • As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.

Moles = \frac{5.8 mol}{1000 mL} \times 100 mL\\= 0.58 mol

  • Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.

Moles = \frac{3.25 mol}{500 mL} \times 100 mL\\0.65 mol

  • Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.

Moles = \frac{1.85 mol}{300 mL} \times 100 mL\\= 0.616 mol

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

8 0
3 years ago
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