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natulia [17]
3 years ago
15

Imagine that you have 0.75L of a 0.10M HCl solution. If you add 0.35L of water, what is the new concentration of the solution?

Chemistry
1 answer:
trapecia [35]3 years ago
4 0

Answer:

1 \: litre \: contain \: 0.10 \: moles \: of \: hydrochloric \: acid \\ 0.75 \: litres \: contain \: (0.75 \times 0.10) \: moles \\  = 0.075 \: moles \\ total \: volume = 0.75 + 0.35 \\  = 1.1 \: litres \\ 1.1 \: litres \: contain \: 0.075 \: moles \\ 1 \: litres \: will \: contain \: ( \frac{1 \times 0.075}{1.1} ) \\  = 0.068 \: mol \:  {l}^{ - 1}

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What portion of your salt solution in ice water system is: a. A mixture? b. A solution?
ahrayia [7]

The salt and water are a homogeneous mixture but when salt dissolves in the water system is called a solution of salt and water.

<h3>What is a mixture? </h3>

A mixture is defined as the combination of two or more substances that are not chemically bonded together.

There are two types of mixture which include:

  • Homogeneous (uniform composition) and

  • Heterogeneous mixtures

When salt is added to the ice water system, it lowers the freezing point of the ice water thereby forming a homogenous mixture of water and salt.

The dissolution of salt in ice water leads to the formation of salt and water solution.

Learn more about mixture here:

brainly.com/question/10677519

8 0
3 years ago
Is o-toluic acid soluble in ether, NaOH?, Is Napthalene soluble in NaOH?
natima [27]
Yes, o-toluic acid is soluble in ether as ether is slightly polar and it is soluble in NaOH because it is likely to form soluble compounds with it.

Naphthalene is insoluble in NaOH.
8 0
4 years ago
What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
AlladinOne [14]

The question is incomplete, here is the complete question:

The given chemical reaction is:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

<u>Answer:</u> The theoretical yield of copper is 44.48 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of aluminium = 12.6 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol

The given chemical equation follows:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of copper

So, 0.467 moles of aluminium will produce = \frac{3}{2}\times 0.467=0.7005mol of copper

Now, calculating the mass of copper  from equation 1, we get:

Molar mass of copper = 63.5 g/mol

Moles of copper = 0.7005 moles

Putting values in equation 1, we get:

0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g

Hence, the theoretical yield of copper is 44.48 grams

4 0
4 years ago
Numerator and denominator are Equal to one another? <br> I don’t get the concept
Alekssandra [29.7K]

It's like saying that if 1 meter is equal to 100 cm,

\frac{100cm}{1m}

or

\frac{1m}{100cm}

You can base the answers from the chart

5 0
3 years ago
How many molecules make up 8.41 moles of Ca2(SO3)?
sammy [17]

Answer:

<h3>5.06282 × 10²⁴ molecules</h3>

Explanation:

The number of molecules of Ca2(SO3) can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 8.41 × 6.02 × 10²³

We have the final answer as

<h3>5.06282 × 10²⁴ molecules</h3>

Hope this helps you

3 0
3 years ago
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