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3 years ago

When using charles law the units of temperature?

Physics

1 answer:

shepuryov [24]3 years ago

3 0

As per Charle's law we can say that if pressure remains constant then

by ideal gas equation we have

$PV = nRT$

$V = \frac{nR}{P} T$

here

$\frac{nR}{P} = constant$

$V = CT$

here

$\frac{V_1}{V_2} = \frac{T_1}{T_2}$

So here temperature must be in SI units

So the unit of temperature must be KELVIN (K)

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A small mailbag is released from a helicopter that is descending steadily at 3 m/s.

mario62 [17]

<u>Answer:</u>

a) Speed of mailbag after 3 seconds = 32.4 m/s

b) Package is 44.1 meter below helicopter

c) If the helicopter was rising steadily at 3.00 m/s

Speed of mailbag after 3 seconds = 26.4 m/s

Package is 44.1 meter below helicopter

<u>Explanation:</u>

a) We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

Initial velocity = 3 m/s, acceleration = 9.8 $m/s^2$ and time = 3 seconds.

v = 3+9.8*3 = 32.4 m/s

Speed of mailbag after 3 seconds = 32.4 m/s

b) We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Velocity of helicopter = 3 m/s, time taken = 3 seconds, acceleration = 0 $m/s^2$ .

$s= 3*3+\frac{1}{2} *0*3^2\\ \\ s=9m$

Distance traveled by helicopter = 9 meter.

Velocity of package = 3 m/s, time taken = 3 seconds, acceleration = 9.8 $m/s^2$ .

$s= 3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 53.1m$

Distance traveled by package = 53.1 meter.

So package is (53.1-9)meter below helicopter = 44.1 m

c) Initial velocity = -3 m/s, acceleration = 9.8 $m/s^2$ and time = 3 seconds.

v = -3+9.8*3 = 26.4 m/s

Speed of mailbag after 3 seconds = 26.4 m/s

Velocity of helicopter = -3 m/s, time taken = 3 seconds, acceleration = 0 $m/s^2$ .

$s= -3*3+\frac{1}{2} *0*3^2\\ \\ s=-9m$

Distance traveled by helicopter = 9 meter.

Velocity of package = -3 m/s, time taken = 3 seconds, acceleration = 9.8 $m/s^2$ .

$s= -3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 35.1m$

Distance traveled by package = 35.1 meter.

So package is (35.1+9)meter below helicopter = 44.1 m

4 0

3 years ago

In which direction does a bag at rest move when a force of 20 newton's is applied from the right?

Olegator [25]

The bag moves to the left.

This is because of Newton's third law of motion that states:

For every action force on a body, there is an opposite and equal reaction force.

Thus pushing the bag from the right makes it move to the left.

8 0

4 years ago

Look at the triangle below.

slega [8]

Answer:

a = 32.48538491

b = 25.59883264

Step-by-step explanation:

To find the length of a, use the sine function:

$sin\alpha = \frac{opposite}{hypotenuse}$

$sin 38 = \frac{20}{a} \\a = \frac{20}{sin38}\\a = 32.48538491$

To find the length of b, use tangent:

$tan\alpha = \frac{opposite}{adjacent}$

$tan 38 = \frac{20}{b} \\b = \frac{20}{sin38}\\b = 25.59883264$

7 0

3 years ago

Which of these forces help protons and neutrons to stay at the center of the Atom

Tcecarenko [31]

Strong nuclear force

8 0

3 years ago

What happens to the position of an object as an unbalanced force acts on?

jarptica [38.1K]

Answer:

Unbalanced forces change the motion of an object. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

5 0

3 years ago

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