Answer:
A.) 4 revolution
B.) 0.2 revolution
C.) 4 seconds
D.) 2.75 m/s
Explanation:
Given that a merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m
Solution
1 revolution = 2πr
Where r = 1.75m
A. How many revolutions will it make in 3 minutes?
(2π × 1.75) / 3
10.9955 / 3
3.665 RPM
Number of revolution = 15 / 3.665
Number of revolution = 4 revolution
B. How many revolutions will it make in 10.0 seconds?
First convert 10 seconds to minutes
10/60 = 0.167 minute
(2π × 1.75) / 0.167
10.9955 / 0.167
65.973
Number of revolution = 15 / 65.973
Number of revolution = 0.2 revolution
C. How long does it take for a person to make 1 complete revolution?
15 = 1 / t
Make t the subject of formula
t = 1/15
t = 0.0667 minute
t = 4 seconds
D. What is the velocity in m/s of person standing on its edge?
Velocity in m/ s will be:
Velocity = (15 × 2pi × r) / 60
Velocity = 164.9334 / 60
Velocity = 2.75 m/s
Answer:
The location of the shear center o is 0.033 or 33 m
Explanation:
Solution
Recall that,
The moment of inertia of the section is = I = 0.05 * 0.4 ^3 /12 + 0.005 * 0.2 ^3/12
= 30 * 10 ^ ⁻⁶ m⁴
Now,
The first moment of inertia is
Q =ῩA = [ (0.1 -x) + x/2] (0.005 * x)
= 0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²
Thus,
The shear flow is,
q = VQ/I
so,
P = (0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²)/ 30 * 10 ^⁻⁶
P = (16.67 x - 83. 33 x²)
The shear force resisted by the shorter web becomes
Vw,₂ = 2∫ = ₀.₁ and ₀ = P (16.67 x - 83. 33 x²) dx = 0.11x
Then,
We take the moment at a point A
∑Mₐ = 0
- ( p * e)- (Vw₂ * 0.3 ) = 0
e = 0.11 p * 0.3/p
which gives us 0.033 m
= 33 m
Therefore the location of the shear center o is 0.033 or 33 m
Note: Kindly find an attached diagram to the question given above as part of the explanation solved with it.
This planet would be known as pluto
Answer:
The momentum of the ball is 500 kg·m/s
Explanation:
The momentum is given by Mass × Velocity
The given parameters are;
The mass of the box = 10 kg
The velocity by which the box is sliding = 50 m/s
Therefore, the momentum of the ball is given as follows;
The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s
The momentum of the ball = 500 kg·m/s
Answer: M^-1 L^-3T^4A^2
Explanation:
From coloumb's law
K = q1q2 / (F × r^2)
Where;
q1, q2 = charges
k = constant (permittivity of free space)
r = distance
Charge (q) = current(A) × time(T) = TA
THEREFORE,
q1q2 = (TA) × (TA) = (TA)^2
Velocity = Distance(L) / time(T) = L/T
Acceleration = change in Velocity(L/T) / time (T)
Therefore, acceleration = LT^-2
Force(F) = Mass(M) × acceleration (LT^-2)
Force(F) = MLT^-2
Distance(r^2) = L^2
From ; K = q1q2 / (F × r^2)
K = (TA)^2 / (MLT^-2) (L^2)
K = T^2A^2M^-1L^-1T^2 L^-2
COLLEXTING LIKE TERMS
T^2+2 A^2 M^-1 L^-1-2
M^-1 L^-3T^4A^2
