Difference between 3.15 m and 2.0 m with the correct number of significant figures?
1 answer:
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Hi there!
Since the object is being pulled at a constant velocity, the forces must be balanced.
Since there is no movement vertically, we must take into account the horizontal forces. We can also assume a positive acceleration to be in the direction of motion.
The acceleration and force due to gravity on an incline is:
a = gsinФ
F = MgsinФ
∑F = -MgsinФ + T
Since it is getting pulled at a constant velocity, ∑F = 0. So:
0 = -MgsinФ + T
MgsinФ = T
Solve for T by plugging in values. Let g = 10 m/s²
T = (120)(10)sin(27) ≈ 545 N
Horizontal velocity: 81.9 km/h
Vertical velocity: 57.4 km/h
Explanation:
We can solve this problem by resolving the velocity vector into its component along the horizontal and vertical direction.
The horizontal velocity of the stunt bike is given by:
where
v = 100 km/h is the magnitude of the velocity
is the angle of projection
Substituting, we find
The vertical velocity instead is given by
where
Substituting,
Learn more about vector components:
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