Name the following covalent compounds CO

Write equations to show whether the solubility of either of the following is affected by pH: (b) Hg₂(CN)₂.

nata0808 [166]

Increasing pH will increase the solubility of the Hg2(CN)2 by shifting equilibrium to right side.

What is the meaning of OH in chemistry?

The chemical group, ion, or radical OH that consists of one atom of hydrogen and one of oxygen and is neutral or negatively charged.

Hg2(CN)2 + 2OH- ----> 2HgO(s) + 2HCN

adding OH- to the mercury(l) cyanide will cause the formation of the solid HgO.

therefore increasing pH will increase the solubility of the Hg2(CN)2 by shifting equilibrium to right side.

Learn more about OH

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3 0

2 years ago

Calculate the number of molecules?

Ann [662]

87.33 X 10^15 molecules

8 0

3 years ago

Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH=1.06×10

kkurt [141]

Answer:

The diameter of the hydrogen $\mathbf{d =1.0605 \times 10^{-10}\ m}$

Explanation:

From the given information:

Using the concept of Bohr's Model, the equation for the angular momentum can be expressed as:

$L = \dfrac{nh}{2 \pi}$

Where the generic expression for angular momentum is:

L = mvr.

replacing the value of L into the previous equation, we have:

$mvr= \dfrac{nh}{2 \pi}$

$v= \dfrac{nh}{2 \pi mr}$ ----- (1)

The electron in the hydrogen atom posses an electrostatic force which gives a centripetal force.

$\dfrac{ke^2}{r^2} = \dfrac{mv^2}{r}$ ----- (2)

replacing the value of v in equation (1) into (2), and taking r as the subject of the formula, we have:

$\dfrac{ke^2}{r} = m (\dfrac{nh}{2 \pi mr})^2$

$ke^2=\dfrac{n^2h^2}{4 \pi^2 mr}$

$r =\dfrac{n^2h^2}{4 \pi^2 mke^2}$

For ground-state n = 1

$h = (6.625 \times 10^{-34} \ J.s)^2$

$m =( 9.1 \times 10^{-31} \ kg)(9 \times 10^9 \ N .m^2/C^2)$

$Ke = (1.6 \times 10^{-19} \ C)^2$

$r =\dfrac{(1)^2(6.625 \times 10^{-34})^2}{4 \pi^2 (9.1 \times 10^{-31} )(9 \times 10^9 ) (1.6 \times 10^{-19})^2}$

$r =\dfrac{4.3890625 \times 10^{-67}}{8.27720295 \times 10^{-57}}$

$\mathbf{r = 5.3025 \times 10^{-11} \ m}$

Therefore, the diameter of hydrogen d = 2r

$\mathbf{d = ( 2 \times 5.3025 \times 10^{-11} \ m})}$

$\mathbf{d =1.0605 \times 10^{-10}\ m}}$

4 0

4 years ago

Determine the geometry for how two acetonitrile molecules would interact with each other

Novay_Z [31]

Acetonitrile molecules are mainly used in lithium batteries as a solvent, and is commonly found in the air from vehicle exhaust.

The geometry on how two acetonitrile molecules would interact with each other is as follows:

_______
------- C======== N

The carbon atom has a single bond to the atom on its left side while having a triple bond on the nitrogen atom on the right side.

8 0

3 years ago

What is the main process by which water moves from land to the atmosphere?

slava [35]

Answer:

isn't that evaporation if not you can just delete my answer-

Explanation:

5 0

3 years ago