When warm air layer traps pollution that is within the earth's surface, a temperature inversion usually takes place. In addition, at temperature inversion happens when the cold air overlays the warm air in the troposphere, which does not usually happen since warm air rises and cold air sinks by principle.
Answer:
x = 2.37 cm
Explanation:
given,
density of oil = 923 kg/m³
height of the block = 4.81 cm
density of the block = 961 Kg/m³
density of water = 1000 Kg/m³
Let x be the depth of the block in the water.
now,
Weight of block will be acting downward.
Buoyancy force will be acting on the block because of the oil and water.
At equilibrium position both weight and the buoyant force will balance.
![\rho_{wood}gh-\rho_{oil}g(h-x)-\rho_{water}gx= 0](https://tex.z-dn.net/?f=%5Crho_%7Bwood%7Dgh-%5Crho_%7Boil%7Dg%28h-x%29-%5Crho_%7Bwater%7Dgx%3D%200)
![961\times 0.0481 - 923\times 0.0481 = -923\times x +1000\times x](https://tex.z-dn.net/?f=961%5Ctimes%200.0481%20-%20923%5Ctimes%200.0481%20%3D%20-923%5Ctimes%20x%20%2B1000%5Ctimes%20x)
![1.8278 = 77 x](https://tex.z-dn.net/?f=1.8278%20%3D%2077%20x)
x = 0.0237 m
x = 2.37 cm
Hence, the block is 2.37 cm in the water.
Length = 3.1748 meters
Width = 3.1748 meters
Height = 3.1748 meters
Surface area = 5 · 3.1748²
Surface area = 50.397 meters²
You have to create table using cubic meters and the unit Kelvin to measure the temperature.
Answer:
d. 149 ⁰C.
Explanation:
Given;
mass of the block of ice, m = 2 kg
specific heat capacity of the ice, C = 2090 J/(kgK)
initial temperature of the ice, t₁ = -90 ⁰C
heat added to the ice, H = 1,000,000 J
let the final temperature of the ice = t₂
The final temperature of the ice after adding the heat is calculated as follows;
![H = mC_{ice} \Delta t\\\\H = mC_{ice} (t_2 - t_1)\\\\1,000,000 = 2 \times 2090 \times (t_2 - (-90))\\\\1,000,000 = 4,180(t_2 +90)\\\\1,000,000 = 4,180t_2 + 376,200\\\\1,000,000 - 376,200 = 4,180t_2\\\\623,800 = 4,180 t_2\\\\t_2 = \frac{623,800}{4,180} \\\\t_2 = 149 \ ^0C](https://tex.z-dn.net/?f=H%20%3D%20mC_%7Bice%7D%20%5CDelta%20t%5C%5C%5C%5CH%20%3D%20mC_%7Bice%7D%20%20%28t_2%20-%20t_1%29%5C%5C%5C%5C1%2C000%2C000%20%3D%202%20%5Ctimes%202090%20%5Ctimes%20%28t_2%20-%20%28-90%29%29%5C%5C%5C%5C1%2C000%2C000%20%3D%204%2C180%28t_2%20%2B90%29%5C%5C%5C%5C1%2C000%2C000%20%3D%204%2C180t_2%20%2B%20376%2C200%5C%5C%5C%5C1%2C000%2C000%20-%20376%2C200%20%3D%204%2C180t_2%5C%5C%5C%5C623%2C800%20%3D%204%2C180%20t_2%5C%5C%5C%5Ct_2%20%3D%20%5Cfrac%7B623%2C800%7D%7B4%2C180%7D%20%5C%5C%5C%5Ct_2%20%3D%20149%20%5C%20%5E0C)
Therefore, the new temperature of the water is 149 ⁰C.