To solve this problem we will use the Froude number that relates the Forces of Inertia with the Forces of Gravity. There will be jump in the downstream only if Froude Number (Fr) is greater than 1 at upstream. Our values are given as,
Then the velocity would be:
The number of Froude is given as,
Where,
V = Velocity
g = Gravity
D = Diameter
Replacing we have that
There will be no Jump, correct answer is B.
Answer:
just free your mind drink water and go outside take fresh air you will get answers.
Explanation:
This a best method to solve the answer.I hope it is helpful
The following scenarios are pertinent to driving conditions that one may encounter. See the following rules of driving.
<h3>What do you do when the car is forced into the guardrail?</h3>
Best response:
- I'll keep my hands on the wheel and slow down gradually.
- The reason I keep my hands on the steering wheel is to avoid losing control.
- This will allow me to slowly back away from the guard rail.
- The next phase is to gradually return to the fast lane.
- Slamming on the brakes at this moment would result in a collision with the car behind.
Scenario 2: When driving on a wet road and the car begins to slide
Best response:
- It is not advised to accelerate.
- Pumping the brakes is not recommended.
- Even lightly depressing and holding down the brake pedal is not recommended.
- The best thing to do is take one foot off the gas pedal.
- There should be no severe twists at this time.
Scenario 3: When you are in slow traffic and you hear the siren of an ambulance behind
Best response:
- The best thing to do at this moment is to go to the right side of the lane and come to a complete stop.
- This helps to keep the patient in the ambulance alive.
- It also provide a clear path for the ambulance.
- Moving to the left is NOT recommended.
- This will exacerbate the situation. If there is no place to park on the right shoulder of the road, it is preferable to stay in the lane.
Learn more about rules of driving. at;
brainly.com/question/8384066
#SPJ1
Answer:
A) б1 = 28 ksi and б2 = -6.02 ksi
B) 1.25
Explanation:
Given data :
Torsional stress = 13 ksi
Alternating bending stress = 22ksi
A) determine yielding factor of safety according to the distortion energy theory
б1,2 = 
± √(22/2)² + 13²
= 11 ± 17
therefore б1 = 28 ksi hence б2 = -6.02 ksi
B) determine the fatigue factor of safety
with properties ; Se = 35ksi, Sy = 60 ksi, Sut = 85 ksi
( б1 - б2 )² + ( б2 - б3 )² + ( б3 - б1 )² ≤ 2 ( Sy / FOS ) ²
( 28 + 6.02 ) ² + ( 6.02 - 0 )² + ( 0 - 28 )² ≤ 2 ( 60 / FOS ) ²
solving for FOS = 1.9
Next we can determine FOS with the use of Goodman criterion
бm / Sut + бa / Se = 1 / FOS
= 0 / 85 + 28/35 = 1 / FOS
making FOS the subject of the equation ; hence FOS = 1.25
