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PilotLPTM [1.2K]
3 years ago
14

8.03 Lab Report Data Answers (I only need the Data as I do not have the time to get the materials and do it myself but I don't n

ecesarrilly need or want all the answers)
https://lti.flvsgl.com/flvs-cat-content/vt2svimqd0nokoo21i93e925bd/flvs-cat-session/educator_chemistry1_v18_gs/module08/lesson03/docs/pre_lab_worksheet.doc
Chemistry
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

subject?

Explanation:

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anuvia, the trade name for sitagliptin, was introduced in 2006 for the treatment of type 2 diabetes. In what type of orbital doe
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Answer: hello your question is poorly written below is the complete question

answer:

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Explanation:

Determining the type of orbital in which the lone pair on each N atom will reside.

From the configuration attached below we can determine the type of orbital and they are ;

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

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2 years ago
Soda is a mixture. The ingredients list for a can of soda is given below.
Rasek [7]

Answer: Compounds

Explanation:

6 0
3 years ago
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Five students performed a Kjeldahl nitrogen analysis of a protein sample. The following weight % nitrogen values were determined
Sunny_sXe [5.5K]

Answer:

G_calculated = 1.756

The outlier should be rejected, as G_cal > G_tab (= 1.463) at 95 % confidence.

Explanation:

The Grubb's test is used for identifying an outlier in data, which is from the same population. For this, a statistical term, G, is calculated for the suspected outlier. If the calculated value is greater than the tabulated G value then the suspected value is rejected. This term is given as,

G_calculated = | suspect value - mean| / s

Here,  suspect value is 13.8, mean is to be taken of all the data (including suspected value). s is the standard deviation of the sample data.

s is calculated from the following formula:

s = (Σ(xi - x)²/(N-1))^1/2

Here, x is the mean, which is 15.24, xi is individual value and N is the total number of data (5).

From the above formula, s is found to be

Standard Deviation, s = 0.820

Now for G value,

G_calculated = | 13.8 - 15.24| / (0.820)

G_ calculated = 1.756

The tabulated G value at 95 % confidence and N -1 (5 - 1 = 4) degree of freedom is, 1.463.

As calculated G (1.756) is greater than the tabulated G (1.463), the value 13.8 is considered an outlier at 95 % confidence.  

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3 years ago
Please help and if u dont know that ok but pleas don't give me the wrong answer​
Levart [38]

Answer: The answer is 2 and 4

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How many valence electrons configuration of oxygen?
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Oxygen had 6 valence electrons
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