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Pani-rosa [81]
4 years ago
15

To apply the principle of superposition to overlapping waves, you should _____ of the individual waves.

Physics
1 answer:
loris [4]4 years ago
6 0
The answer is d I believe
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A magnet is moved in and out of a coil of wire connected to a high-resistance voltmeter. If the number of coils doubles, the ind
Varvara68 [4.7K]

Answer:

A. Doubles.

Explanation:

In an electromagnetic device such as a generator, when a wire (conductor) moves through the magnetic field between the South and North poles of a magnet, an electromotive force (e.m.f) is usually induced across a wire

The mode of operation of a generator is that a metal core with copper tightly wound to it (conductor coil) rotates rapidly between the two (2) poles of a horseshoe magnet type. Thus when the conductor coil rotates rapidly, it cuts the magnetic field existing between the poles of the horseshoe magnet and then induces the flow of current.

When a high-resistance voltmeter is connected to an electric circuit, a deflection will arise due to the flow of electricity. Moving the magnet towards the coil of wire will cause the needle of the high-resistance voltmeter to move in one direction. Also, as the magnet is moved out from the coil of wire, the needle of the high-resistance voltmeter moves in the opposite direction.

In this scenario, a magnet is moved in and out of a coil of wire connected to a high-resistance voltmeter. If the number of coils doubles, the induced voltage doubles because the number of turns (voltage) in the primary winding is directly proportional to the number of turns (voltage) in the secondary winding.

4 0
3 years ago
If ball C is 3 times the volume of ball D and ball D has 1/3 the mass of ball C, which has the greater density?
Alex Ar [27]

Answer:

They have same density

Explanation:

The density of an object is defined as

d=\frac{m}{V}

where

m is the mass of the object

V is its volume

Let's call m_c and V_c the mass and the volume of ball C, respectively. Therefore, the density of ball C is:

d_c = \frac{m_c}{V_c}

We know that the volume of ball C is 3 times the volume of ball D, so

V_c = 3 V_d \rightarrow V_d = \frac{V_c}{3}

And we also know that ball D has 1/3 the mass of ball C:

m_d = \frac{m_c}{3}

So, the density of ball D is:

v_d = \frac{m_d}{V_d}=\frac{m_c/3}{V_d/3}=\frac{m_c}{V_c}=d_c

Therefore, the two balls have same density.

6 0
3 years ago
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