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ad-work [718]
3 years ago
12

A certain shade of blue has a frequency of 7.24 × 1014 Hz. What is the energy of exactly one photon of this light?

Physics
2 answers:
ANEK [815]3 years ago
4 0
E = hf

E = 6.63* 10 ⁻³⁴ * 7.24* 10¹⁴

<span>E = 4.80012 × 10⁻¹⁹ J</span>
Kitty [74]3 years ago
4 0
The energy of the photon is proportional to frequency of the photon. The constant of proportionality here is called Planck's constant with a value of 6.62607004 × 10-34 m2 kg / s. In this case, substituting to the formula E = h v where h is the constant and v is the frequency, the answer is <span>4.80 × 10^-19 Joules</span>
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Select the statements that are TRUE. Electrophilic aromatic substitution reactions have energies of activation that are very low
NikAS [45]

Answer:

Addition reactions with benzenes lead to the loss of aromaticity.

Benzene and its derivatives undergo a type of substitution reaction in which a hydrogen atom is replaced by a substituent, but the stable aromatic benzene ring is regenerated at the end of the mechanism.

Benzene and its derivatives tend to undergo electrophilic aromatic substitution reactions.

Explanation:

5 0
3 years ago
Is this statement true or false? The next generation of nuclear power plants being built in California and South Africa are even
alexira [117]

Answer:

True

Explanation:

Modern safer and cheaper nuclear reactors can not only meet the range of our long term energy demands, they can also fight global warming.

Modern techniques provide ways to reduce radioactive waste amount. "A closed fuel cycle may be switched on for new kinds of nuclear plants. Alternatively, the waste is chemically dissuaded to transform the reusable element into fuel. This implies that nuclear waste would not be buried.

8 0
3 years ago
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kipiarov [429]

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4 0
2 years ago
Read 2 more answers
The wavelength of light is 5000 angstrom. Express it in nm and m.
Ierofanga [76]

Answer:

1 angstrom = 0.1nm

5000 angstrom = 5000/1 × 0.1nm

<h3>= 500nm</h3>

1 \:  angstrom = 1 \times  {10}^{ - 10} m

5000 angstrom = 5000 × 1 × 10^-10

<h3>= 5 × 10^-7 m</h3>

Hope this helps you

7 0
3 years ago
A boy throws a ball of mass 0.22 kg straight upward with an initial speed of 29 m/s. When the ball returns to the boy, its speed
maksim [4K]

Answer:

The work is -67.76 J

Explanation:

The law of conservation of energy is considered one of one of the fundamental laws of physics and states that the total energy of an isolated system remains constant. except when it is transformed into other types of energy.

This is summed up in the principle that energy can neither be created nor destroyed in the universe, only transformed into other forms of energy.

In this case you must calculate the loss of kinetic energy. This loss is actually the work done against the resistive force in the air. Friction is the only force other than gravity that acts on the ball.

So, the loss of kinetic energy is \frac{1}{2} *m*(vf^{2} -vi^{2} )

You know:

  • mass=m=0.22 kg
  • Initial velocity of the ball: vi= 29 \frac{m}{s}

Final velocity of the ball: vf= 15 \frac{m}{s}

Replacing:

\frac{1}{2} *0.22 kg*(15^{2} -29^{2} )= -67.76 J

Friction work is always negative because friction is always against displacement.

<u><em>The work is -67.76 J</em></u>

5 0
3 years ago
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