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ad-work [718]
3 years ago
12

A certain shade of blue has a frequency of 7.24 × 1014 Hz. What is the energy of exactly one photon of this light?

Physics
2 answers:
ANEK [815]3 years ago
4 0
E = hf

E = 6.63* 10 ⁻³⁴ * 7.24* 10¹⁴

<span>E = 4.80012 × 10⁻¹⁹ J</span>
Kitty [74]3 years ago
4 0
The energy of the photon is proportional to frequency of the photon. The constant of proportionality here is called Planck's constant with a value of 6.62607004 × 10-34 m2 kg / s. In this case, substituting to the formula E = h v where h is the constant and v is the frequency, the answer is <span>4.80 × 10^-19 Joules</span>
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John throws a rock down with speed 14 m/s from the top of a 30 m tower. If air resistance is negligible, what is the rock's spee
astra-53 [7]

The final velocity of the rock before it touches the ground is 28 m/s.

Answer:

Explanation:

As the rock is thrown down, this means the acceleration due to gravity will be exerting on the rock. So the rock will be exhibiting a free fall motion. Thus, the acceleration of the rock will be equal to the magnitude of acceleration due to gravity. Then using the third equation of motion, we can determine the final velocity of the rock provided the values for initial velocity, displacement and acceleration is given in the problem itself.

So the acceleration is equal to 9.8 m/s² due to its free fall motion and displacement will be equal to the height of the tower which is given as 30 m. And the initial speed of the rock is stated as 14 m/s. The initial speed is represented as u, final speed is represented as v, displacement is represented as s and acceleration is represented as a.

2as=v^{2}-u^{2}

Then, 2 × 9.8 × 30 = v²-(14)²

v²=784

v= 28 m/s

So the final velocity of the rock before it touches the ground is 28 m/s.

8 0
4 years ago
A quarterback takes the ball from the line of scrimmage, runs backward for 12.1 yds, then runs sideways parallel to the line of
Over [174]

Answer:

The answer is 35.45 yds

Explanation:

You have to picture this to be able to understand it better (see attachment).

Start at the origin which is when the quarterback (QB) takes the ball. He runs backwards 12.1 yards, runs sideways for 19.8 yards (it doesn´t matter if he runs right or left), then he throws the ball forward 41.5 yards. If you look at the attachment, you can see I drew the path that the football followed. And then connected the dots from the origin and finish. The distance between those two points is the magnitude of the resultant displacement.

In order to calculate it, all you need to do is use the Pythagoream theorem, which says that the square of the hypotenuse equals the sum of the squares of the legs a and b of the triangle rectangle.

  1. R^{2} = a^{2} + b^{2} then solve for R
  2. R = \sqrt{a^{2}+b^{2}  }

In this case, you know the length of leg a to be 19.8 yards which how much it moves sideways. And then, to get the length of leg b, all you need to do is substract how much it moved backwards from the 41.5yards forward displacement. This results in b leg being 29.4 yards long.

Now you have a triangle with:

  • a = 19.8 yards
  • b = 29.4 yards

Substituting this numbers in the equation:

  • R = \sqrt{19.8^{2}+29.4^{2}  }
  • R = 35.45 yards

3 0
3 years ago
The
Fofino [41]

Answer:

Wave Variables

In the chapter on motion in two dimensions, we defined the following variables to describe harmonic motion:

Amplitude—maximum displacement from the equilibrium position of an object oscillating around such equilibrium position

Frequency—number of events per unit of time

Period—time it takes to complete one oscillation

For waves, these variables have the same basic meaning. However, it is helpful to word the definitions in a more specific way that applies directly to waves:

].

Explanation:

3 0
3 years ago
Read 2 more answers
Create a model in the space below that demonstrates how action potentials ensue. A sample model can be found under the Unit Pack
Pepsi [2]

Answer:

K+NA+30

Explanation:

8 0
3 years ago
The sound source of a ship's sonar system operates at a frequency of 18.0 kHzkHz . The speed of sound in water (assumed to be at
Flura [38]

Answer:

Explanation:

a ) wave length of waves in water

= velocity / frequency

= 1482 / (18 x 1000)

= .0823 m

= 8.23 cm

b ) Applying Doppler's effect relation

frequency of reflected wave

= 18000 [ 1482 / (1482 - 4.95 ) ]

= 18000 x 1.003385

= 18061

Difference in frequency= 61 Hz

5 0
3 years ago
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