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ad-work [718]
3 years ago
12

A certain shade of blue has a frequency of 7.24 × 1014 Hz. What is the energy of exactly one photon of this light?

Physics
2 answers:
ANEK [815]3 years ago
4 0
E = hf

E = 6.63* 10 ⁻³⁴ * 7.24* 10¹⁴

<span>E = 4.80012 × 10⁻¹⁹ J</span>
Kitty [74]3 years ago
4 0
The energy of the photon is proportional to frequency of the photon. The constant of proportionality here is called Planck's constant with a value of 6.62607004 × 10-34 m2 kg / s. In this case, substituting to the formula E = h v where h is the constant and v is the frequency, the answer is <span>4.80 × 10^-19 Joules</span>
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When the distance between two interacting objects doubles, the gravitational force is
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F=GMm/r^2

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3 years ago
If the range of a projectile's trajectory is six times larger than the height of the trajectory, then what was the angle of laun
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Answer:

H = 1/2 g t^2    where t is time to fall a height H

H = 1/8 g T^2   where T is total time in air  (2 t  = T)

R = V T cos θ       horizontal range

3/4 g T^2 = V T cos θ       6 H = R    given in problem

cos θ = 3 g T / (4 V)           (I)

Now t = V sin θ / g     time for projectile to fall from max height

T = 2 V sin θ / g

T / V = 2 sin θ / g

cos θ = 3 g / 4 (T / V)     from (I)

cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ

tan θ = 2/3      

θ = 33.7 deg

As a check- let V = 100 m/s

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Vy = 100 sin 33,7 = 55.5

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