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ad-work [718]
3 years ago
12

A certain shade of blue has a frequency of 7.24 × 1014 Hz. What is the energy of exactly one photon of this light?

Physics
2 answers:
ANEK [815]3 years ago
4 0
E = hf

E = 6.63* 10 ⁻³⁴ * 7.24* 10¹⁴

<span>E = 4.80012 × 10⁻¹⁹ J</span>
Kitty [74]3 years ago
4 0
The energy of the photon is proportional to frequency of the photon. The constant of proportionality here is called Planck's constant with a value of 6.62607004 × 10-34 m2 kg / s. In this case, substituting to the formula E = h v where h is the constant and v is the frequency, the answer is <span>4.80 × 10^-19 Joules</span>
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1) Initial upward acceleration: 6.0 m/s^2

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Explanation:

1)

There are two forces acting on the rocket at the beginning:

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g=9.8 m/s^2 is the acceleration of gravity

- The thrust of the motor, T, in the upward direction, of magnitude

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Solving for a, we find the initial acceleration:

a=\frac{T-mg}{m}=\frac{3.0\cdot 10^5-(1.9\cdot 10^4)(9.8)}{1.9\cdot 10^4}=6.0 m/s^2

2)

When the rocket reaches an altitude of 5000 m, its acceleration has increased to

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The reason for this increase is that the mass of the rocket has decreased, because the rocket has burned some fuel.

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T-m'g=m'a'

where

m' is the new mass of the rocket

Re-arranging the equation and solving for m', we find

m'=\frac{T}{g+a}=\frac{3.0\cdot 10^5}{9.8+6.9}=1.8\cdot 10^4 kg

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m=1.9 \cdot 10^4 kg

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