It showed that atoms can be divided into smaller parts.
It showed that all atoms contain electrons.
Explanation:
The experiment carried out by J.J Thomson on the gas discharge tube by passing electric current through a tube filled with many different gases provided a good insight into the structure of an atom.
This experiment led to the development of the plum pudding model of the atom.
- Cathode rays and it properties were discovered in this set up.
- It furnished the scientific community with evidences that atoms can be divided into smaller parts.
- Since atoms now contain some subatomic particles, they can be broken down in like manner into further bits.
- The cathode rays which were later termed electrons became a fundamental particles known for every atom.
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The balanced equation would be 
<h3>Electrochemical equations</h3>
Zn reacts with Cu solution according to the following equation:
In the reaction, 
is reduced according to the following: 
While Zn is oxidized according to the following: 
Thus, giving the overall equation of;
More oxidation-reduction equations can be found here: brainly.com/question/13699873
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Answer: “We live on a hunk of rock and metal that circles a humdrum star that is one of 400 billion other stars that make up the Milky Way Galaxy which is one of billions of other galaxies which make up a universe which may be one of a very large number, perhaps an infinite number, of other universes. That is a perspective on human life and our culture that is well worth pondering.”
― Carl Saga
Is this it mate?
Answer:
The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol
Explanation:
The chemical reaction of the combustion of methane is given as follows;
CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)
Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor
Where:
CH₄ (g): Hf = -74.6 kJ/mol
CO₂ (g): Hf = -393.5 kJ/mol
H₂O (g): Hf = -241.82 kJ/mol
Therefore, the combustion of 1 mole of methane releases;
-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol
Hence the combustion of 2 moles of methae will rellease;
2 × -802.54 kJ/mol or 1,605.08 kJ/mol.
100% find the gfm of both sides then divide
