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Naya [18.7K]
2 years ago
14

I have five less protons than the least massive metalloid in the fourth period. Who am I?

Chemistry
1 answer:
exis [7]2 years ago
6 0

Answer:

You are the Cobalt

Explanation:

The least massive metalloid in the fourth period is Germanium, and it have 32 protons. If you have 5 less protons: 32 - 5 = 27 protons. The element with 27 protons is Cobalt

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An ionic bond can be formed when one or more electrons are
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Answer:

Are transferred completely from the valence shell of an element to the other

Explanation:

Basically, to form a chemical bond, you either transfer or you share. When you share, it is a case of covalent bonding which can be in several other forms. When there is a transfer, it is a case of ionic bonding.

The basic explanation for this is that while some atoms are electronically sufficient, some are electronically deficient. This means while some atoms are having an excess number of electrons, then some are having less number of electrons.

To satisfy both parties, there must be a transfer if electrons between the two parties. While the one with the excess numbers serves as the donor, the one with insufficient number of electrons serve as the acceptor

8 0
2 years ago
What is the molar mass of Fe(NO3)2?
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I believe that the molar mass is 342.34g/mol
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3 years ago
Based on the balanced equation 2C2H2 + 5O2 → 4CO2 + 2H2O calculate the number of excess reagent units remaining when 52 C2H2 mol
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Answer:

20 molecules of oxygen gas remains after the reaction.

Explanation:

2C_2H_2 + 5O_2\rightarrow 4CO_2 + 2H_2O

Molecules of ethyne = 52

Molecules of oxygen gas = 150

According to reaction, 2 molecules of ethyne reacts with 5 molecules of oxygen gas.

Then 52 molecules of ethyne will react with:

\frac{5}{2}\times 52=130 molecules of oxygen gas.

As we can see that we have 150 molecules of oxygen gas, but 52 molecules of ethyne will react with 130 molecules of oxygen gas. So, this means that ethyne is a limiting reagent and oxygen gas is an excessive reagent.

Remaining molecules of recessive reagent = 150 - 130 = 20

20 molecules of oxygen gas remains after the reaction.

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