I have five less protons than the least massive metalloid in the fourth period. Who am I?
1 answer:
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Answer : The energy released by an electron in a mercury atom to produce a photon of this light must be,
Explanation : Given,
Wavelength =
conversion used :
Formula used :
As,
So,
where,
= frequency
h = Planck's constant =
= wavelength =
c = speed of light =
Now put all the given values in the above formula, we get:
Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be,