Answer:
The torque must be applied to the wheel is 15.7 N-m.
Explanation:
Given that,
Mass of the wheel of cylinder, m = 50 kg
Diameter of the wheel, d = 1 m
Radius, r = 0.5 m
Initial speed off the wheel is 0
Final angular speed of the wheel, 120 rev/min = 12.56 rad/s
Angular displacement, 
The torque is given by :

So, the torque must be applied to the wheel is 15.7 N-m.
Answer:
Explanation:
Given:
- gravitational field strength of moon at a distance R from its center,

- Distance of the satellite from the center of the moon,

<u>Now as we know that the value of gravity of any heavenly body is at height h is given as:</u>

∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.
Answer:
(a) 
(b) 
Given:
Time period of Pulsar, 
Equatorial radius, R = 15 Km = 15000 m
Spinning time, 
Solution:
(a) To calculate the value of the centripetal acceleration,
on the surface of the equator, the force acting is given by the centripetal force:

(1)
where

(2)
Now, from (1) and (2):



(b) To calculate the tangential acceleration of the object :
The tangential acceleration of the object will remain constant and is given by the equation of motion as:

where
u = 



I normal bubble starts at the speed of 10mph then speeds up +5 each second. so this would be 600 meters. also, it depends on the density of the water and whats inside the water or liquid in the lake. there are many factors that will change this speed.