The area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
<h3>What is the area of the kite figure?</h3>
The area of the kite figure is half of the product of its diagonals. Area of kite figure can be find out using the following formula.
Here, p and q are the diagonals of the kite.
The length of the first diagonal of the kite figure is,
p=6+15
p=21 cm
The length of the second diagonal of the kite figure is,
q=8+8
q=16 cm
Thus, the area of kite figure is:
Thus, the area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
Learn more about the area of kite here;
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Answer:
1. y=mx+b
(5 , 5) (10 , 10)
5m+b=5 10m+b=10
10m+b-5m-b=5
5m=5
m=1
5+b=5
b=0
So for 1---10s the slope is: y = x
2. y=mx+b
(10 , 10) (35 , 10)
10m+b=10 35m+b=10
35m+b-10m-b=0
25m=0
m=0
b=10
So for 10-----35s the slope is: y=10
3. y=mx+b
(35 , 10) (0 , 0)
35m+b=10 b=0
35m=10
m=2/7
So for 35----40s the slope is: y= 2/7 x
Answer:
Step-by-step explanation:
( g ° f )(x) = ( x + 7 )² = x² + 14x + 49
20 + 3(x² + 14x + 49) = - 34
20 + 3x² + 42x + 147 = - 34
3x² + 42x + 201 = 0 ⇔ x² + 14x + 67 = 0
D = 196 - 268 = - 72 < 0
There is no any roots in set of real numbers.
The values of x in set of complex numbers are:
= 
± 
= - 7 ± 3√2 i
Following PEDMAS it'd be
=0
0+(50x1)-60-(60x0)+10
0+50-60-0+10
50-60+10
-10+10=0
Hope this helps. :)
The subspace has dimension 3.
Intuitively, you can think that you're removing one degree of freedom from 
. In fact, this space is generated by the following span:
Since the first and third coordinate must be the same, we have 
. So, the span becomes
which is the same as
And so you can see that the space is generated by three vectors.
