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3 years ago

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Succinic acid is a substance produced by lichens. Chemical analysis indicates it is composed of 40.68% C, 5.08% H, and 54.24% O.

Determine the empirical formula.

1 answer:

zimovet [89]3 years ago

5 0

Answer:

C₂H₃O₂

Explanation:

Assume that you have 100 g of the compound.

Then you have 40.68 g C, 5.08 g H, and 54.24 g O.

1. Calculate the <em>moles of each element</em>.

Moles of C = 40.68 × 1/12.01 = 3.387 mol C

Moles of H = 5.08 × 1/1.008 = 5.010 mol H

Moles of O = 54.24 × 1/16.000 = 3.390 mol O

===============

2. Calculate the <em>molar ratios</em>.

Divide all values by the smallest number.

C: 3.387/3.387 = 1

H: 5.010/3.387 = 1.479

O: 3.390/3.387 = 1.001

===============

3. <em>Multiply each ratio by 2 </em>

C: 2 × 1 = 2

H: 2 × 1.479 = 2.958

O: 2 × 1.001 = 2.002

===============

4. Determine <em>the empirical formula</em>

Round off all numbers to the closest integer.

C: 2

H: 3

O: 2

The empirical formula is C₂H₃O₂.

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Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

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The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

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To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

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$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

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