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leva [86]
3 years ago
8

The scientific principle involve in the inflation of an airbag. Explain how this Device protects the drivers and the front passe

nger from injuries.​
Physics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

The deployment of an airbag protects the head and upper body of the driver and reduces some of the force exerted on the driver by the seatbelt. In the event that anyone in the vehicle is forced forward or to the side, they will come into contact with the airbag instead of the hard vehicle interior.

Explanation:

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Two long parallel wires are separated by forty centimeters and carry oppositely-directed currents of ten amperes. Find the magni
Softa [21]

Answer:

1.04μT

Explanation:

Due to both wires have opposite currents, the magnitude of the total magnetic field is given by

B_T=\frac{\mu_o I}{2 \pi r_1}-\frac{\mu_o I}{2 \pi r_2}

I: electric current = 10A

mu_o: magnetic permeability of vacuum = 4pi*10^{-7} N/A^2

r1: distance from wire 1 to the point in which B is measured.

r2: distance from wire 2.

The distance between wires is 40cm = 0.4m. Hence, r1=0.2m r2=0.6m

By replacing in the formula you obtain:

B_T=\frac{(4\pi *10^{-7}N/A^2)(10A)}{2\pi}(\frac{1}{0.4m}-\frac{1}{0.6m})=1.04*10^{-6}T =1.04\mu T

hence, the magnitude of the magnetic field is 1.04μT

4 0
3 years ago
Hi, I need some science help ASAP. Here's the question:
ch4aika [34]

Answer:

Mass of the box is 25kg

Explanation:

From Newton's second law of motion

Force= mass. acceleration

With the symbol

F=m.a

m=F/a      m=(50N)/(2m/s²)

                m=25kg

7 0
3 years ago
A heavy ball with a weight of 150 N is hung from the ceiling of a lecture hall on a 4.1-m-long rope. The ball is pulled to one s
AlladinOne [14]

Answer:

The tension in the rope is 262.88 N

Explanation:

Given:

Weight W = 150 N

Length of rope r = 4.1 m

Initial speed of ball v = 5.5 \frac{m}{s}

For finding the tension in the rope,

First find the mass of rod,

mg = 150                          ( g = 9.8 \frac{m}{s^{2} } )

  m = \frac{150}{9.8}

  m = 15.3 kg

Tension in the rope is,

  T = mg + \frac{mv^{2} }{r}

  T = 150 + \frac{15.3 \times (5.5)^{2} }{4.1}

  T = 262.88 N

Therefore, the tension in the rope is 262.88 N

7 0
3 years ago
If a box is pushed 5.0 m across a floor using a force of 35 N, how much work was done?
aniked [119]

Answer:

175J

Explanation:

Work done is given by the product of the force applied and the distance travelled as a result of that force.

Or in formula , W=F×d

Thus,

W= 35 × 5.0=175 J or 1.8 e2 J

3 0
3 years ago
Which location would the selected items BEST fit on the nuclear energy diagram?
Sladkaya [172]
Your answer is c) Fusion

7 0
3 years ago
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