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leva [86]
3 years ago
8

The scientific principle involve in the inflation of an airbag. Explain how this Device protects the drivers and the front passe

nger from injuries.​
Physics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

The deployment of an airbag protects the head and upper body of the driver and reduces some of the force exerted on the driver by the seatbelt. In the event that anyone in the vehicle is forced forward or to the side, they will come into contact with the airbag instead of the hard vehicle interior.

Explanation:

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Awave has a period of 1. What is its frequency?
Andrei [34K]

Answer:

Frequency, f = 1 unit

Explanation:

It is given that,

Period of the wave, T = 1 unit

We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :

T=\dfrac{1}{f}

Or

f=\dfrac{1}{T}

f=\dfrac{1}{1\ units}

f = 1 unit

So, the frequency of the wave is 1 unit. Hence, this is the required solution.

4 0
3 years ago
How do you determine the label for each vertex when you perform the triangle triangle in problem 5
Rasek [7]
How do you ask a question but don’t know the answer we will never know
4 0
2 years ago
A displacement vector begins at the point (2,3) on a Cartesian plane and ends at (5, 7). Calculate the length of this vector
babunello [35]

Answer:

The length is d = 5

Explanation:

We must identify the respective coordinates of both points.

(x1,y1) = (2,3)

(x2,y2) = (5,7)

Now we know the distance equation of a straight line:

d=\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} } \\d=\sqrt{(5-2)^{2} +(7-3)^{2} }\\ d=\sqrt{9+16} \\d=5

3 0
3 years ago
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
Genrish500 [490]

Explanation:

Given:

Final speed of mass A = Va

Final speed of mass B = Vb

Mass of A = Ma

Mass of B = Mb

Ma = 2 × Mb

By conservation of linear momentum,

0 = Ma × Va + Mb × Vb

0 =  2 × Mb × Va + Mb × Vb

Vb = - 2 × Va              

Energy of the spring, U = 1/2 × k × x^2

1/2 k x² = 1/2 × Ma × Va² + 1/2 × Mb × Vb²

35 = 1/2 × Ma × Va² + 1/2 × Mb × Vb²

Ma × Va² + Mb × Vb² = 70

2 × Mb (-Vb/2)² + Mb × Vb² = 70

1/2 × Mb × Vb² + Mb × Vb² = 70

3/2 × Mb × Vb² = 70

Mb × Vb² = 140/3

= 46.7 J

Ma = 2 × Mb and Vb = - 2 × Va

Ma/2 × (4 × Va²) = 140/3

Ma × Va² = 70/3

Kinetic energy of mass A, KEa = 1/2 × Ma × Va² = 23.3 J

Kinetic energy of mass B = 1/2 × Mb × Vb² = 46.7 J

8 0
2 years ago
Is there any possibility to make 100% efficient system
Ganezh [65]

Answer:

yes

Explanation:

its awesome

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