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frutty [35]
3 years ago
12

A 100 kg marble slab falls off a skyscraper and falls 200 m to the ground without hitting anyone. Its fall stops within millisec

onds, so that there is no loss of thermal energy to its surroundings if its temperature is measured immediately after it stops. By how much has its temperature changed as a result of the fall, if we ignore energy gained or lost as a result of its interaction with the atmosphere? Cmarble = 860 J/(kg oC) 0.57 °C 1.14 °C 2.28 °C 4.56 °C
Physics
1 answer:
Radda [10]3 years ago
7 0

Answer:

Δ T = 2.28°C

Explanation:

given,

mass of marble = 100 Kg

height of fall = 200 m

acceleration due to gravity = 9.8 m/s²

C_marble = 860 J/(kg °C)

using conservation of energy

Potential energy = heat energy

  m g h = m C_{marble}\Delta T

  g h =C_{marble}\Delta T

  \Delta T= \dfrac{g h}{C_{marble}}

  \Delta T= \dfrac{9.8 \times 200}{860}

        Δ T = 2.28°C

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mafiozo [28]

Answer:

   t = 0.24 s

Explanation:

As seen in the attached diagram, we are going to use dynamics to resolve the problem, so we will be using the equations for the translation and the rotation dyamics:

Translation:  ΣF = ma

Rotation:      ΣM = Iα ; where α = angular acceleration

Because the angular acceleration is equal to the linear acceleration divided by the radius, the rotation equation also can be represented like:

                    ΣM = I(a/R)

Now we are going to resolve and combine these equations.

For translation:     Fx - Ffr = ma

We know that Fx = mgSin27°, so we substitute:

         (1)                 mgSin27° - Ffr = ma  

For rotation:         (Ffr)(R) = (2/3mR²)(a/R)

The radius cancel each other:

        (2)                Ffr = 2/3 ma

We substitute equation (2) in equation (1):

                            mgSin27° - 2/3 ma = ma

                            mgSin27° = ma + 2/3 ma

The mass gets cancelled:

                            gSin27° = 5/3 a

                            a = (3/5)(gSin27°)

                            a = (3/5)(9.8 m/s²(Sin27°))

                            a = 2.67 m/s²

If we assume that the acceleration is a constant we can use the next equation to find the velocity:

                           V = √2ad; where  d = 0.327m

                           V = √2(2.67 m/s²)(0.327m)

                            V = 1.32 m/s

Because V = d/t

                             t = d/V

                             t = 0.327m/1.32 m/s

                             t = 0.24 s

7 0
3 years ago
A 0.20 mass on a horizontal spring is pulled back a certain distance and released. The maximum speed of the mass is measured to
olga55 [171]

Answer:

d

Explanation:

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K=½mv²===> K=½×0.2×(0.2)²===> 0.1(0.04)===> 0.004

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4 0
3 years ago
1. Which letter represents the location of the battery in this diagram?
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Answer:

location of battery in this diagram is at A and location of switch is at B.

4 0
3 years ago
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47. A car travels 85 km in the first half hour of a trip. The car continues to travel for 2 more hours and travels 200 km. What
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Answer: 114 km/h

Explanation:

The formula for determining average speed is expressed as

Average speed = total distance/total time

The car travels 85 km in the first half hour of a trip. The car continues to travel for 2 more hours and travels 200 km. It means that the total distance that the car travels is

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The total time spent by the car is

0.5 + 2 = 2.5 hours

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3 0
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Phoenix [80]

Answer:

The temperature of the core raises by 2.8^{o}C every second.

Explanation:

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It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius

Thus reactor core whose mass is 1.60\times 10^{5}kg will require

0.3349\times 1.60\times 10^{5}kJ\\\\=0.53584\times 10^{5}kJ

energy to raise it's temperature by 1 degree Celsius in 1 second

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\frac{150\times 10^{6}}{0.53584\times 10^{8}}=2.8^{o}C/s

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2 years ago
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