We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

2 years ago

A merchant mixed 10 lb of a cinnamon tea with 2 lb of spice tea. The 12-pound mixture cost $13. A second mixture included 16 lb

Sonja [21]

Step-by-step explanation:

Let's say c is the price of cinnamon tea, and s is the price of spice tea.

10c + 2s = 13

16c + 8s = 28

Divide the second equation by 4:

4c + 2s = 7

Subtract from the first equation:

6c = 6

c = 1

Use any equation to find s.

s = 1.5

Therefore, the cinnamon tea costs $1 per pound and the spice tea costs $1.50 per pound.

3 0

2 years ago

Use the graph of the function to evaluate f(2).

oee [108]

Do you have the picture?

6 0

3 years ago