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k0ka [10]
3 years ago
12

3. The number of children in 10 families of a locality are:

Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0

Answer:

Step-by-step explanation:

Mean = 2+4+3+4+2+0+3+5+1+6/ 10

= 30/10 = 3

Marat540 [252]3 years ago
4 0

Answer:

1 or 2 (1.45 to be exact)

Step-by-step explanation:

Mean is always the numbers added together, divided by the amount of numbers.

2+4+3+4+2+0+3+4+1+6=29

29 divided by 10 is 1.45

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I need some help graphing this
Romashka [77]

Answer:

1.512445e+216

Step-by-step explanation:

3 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
How many tens equal 7000 ones ?
serg [7]

My answer was wrong, I'm am very sorry

8 0
3 years ago
Can anyone tell me if this is right
Rashid [163]

Answer:

yes it is correct

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Mrs. chill has 26 yards of ribbon. She places equal amounts on 3 different spools to sell. How much ribbon in yards are on each
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8.6 yards are on each spool
6 0
3 years ago
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