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sukhopar [10]
3 years ago
10

(C)

Chemistry
1 answer:
kari74 [83]3 years ago
6 0

Answer:

177.3kg C₂₁H₄₄

Explanation:

Based on the chemical reaction:

C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂

<em>Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.</em>

<em />

To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:

<em>Moles Ethene -Molar mass: 28.05g/mol-</em>

50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene

<em>Moles C₂₁H₄₄:</em>

1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄

<em>Mass C₂₁H₄₄:</em>

589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =

<h3>177.3kg C₂₁H₄₄</h3>
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Answer:

Explanation:

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Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

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De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

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Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

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Now we have to calculate the mass of NaBr.

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