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3 years ago

(C)

Chemistry

1 answer:

kari74 [83]3 years ago

6 0

Answer:

177.3kg C₂₁H₄₄

Explanation:

Based on the chemical reaction:

C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂

Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.

To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:

Moles Ethene -Molar mass: 28.05g/mol-

50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene

Moles C₂₁H₄₄:

1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄

Mass C₂₁H₄₄:

589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =

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8_murik_8 [283]

Answer:

Static Electricity.

Explanation:

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2 years ago

A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af

larisa86 [58]

Explanation:

The given reaction is as follows.

$HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)$

Hence, number of moles of NaOH are as follows.

n = $0.05 L \times 0.1 M$

= 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

n = $0.025 L \times 0.1 M$

= 0.0025 mol

According to ICE table,

$HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)$

Initial: 0.005 mol 0.0025 mol 0 0

Change: -0.0025 mol -0.0025 mol +0.0025 mol

Equibm: 0.0025 mol 0 0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

[HA] = $\frac{0.0025 mol}{V}$

[NaA] = $\frac{0.0025 mol}{V}$

$[A^{-}] = [NaA] = \frac{0.0025 mol}{V}$

Now, we will calculate the $pK_{a}$ value as follows.

pH = $pK_{a} + log \frac{A^{-}}{HA}$

$pK_{a} = pH - log \frac{[A^{-}]}{[HA]}$

= $3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}$

= 3.42

Thus, we can conclude that $pK_{a}$ of the weak acid is 3.42.

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3 years ago

Write the reaction rate expressions for the following reactions? 2H2+O2_____2H2O

Nezavi [6.7K]

Answer:

see attachment

Explanation:

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A car with a mass of 1360 kg accelerate from 120 m/s 2 to 520 m / s in 8 seconds.what is the acceletation of the car

Keith_Richards [23]

The mass isnt relevant
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chubhunter [2.5K]

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2 years ago