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Levart [38]
3 years ago
10

Is this right? I’ll mark brainliest if you’re correct

Mathematics
1 answer:
ira [324]3 years ago
7 0

Answer:

No its independent

Step-by-step explanation:

because you'll have to divide and stuff

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Max was on vacation twice as long as Jared and half as long as Wesley. The boys were on vacation a total of 3 weeks. How many da
GuDViN [60]
Lets say W=Wesley, M=Max, and J=Jared.
So your equations are M=2J, 2M=W, and M+J+W=21days(3 weeks)
So substituting M and W into M+J+W=21 gives you 2J+J+2M=21, substitute M again, to get 2J+J+4J=21 so you get 7J=21 so J= 3 days. Using J=3, substitute in to find M, using M=2J, so M=2(3) so M=6 and using that, substitute into 2M=W, so 2(6)=W so W=12. And 12+6+3=21 to check.

6 0
3 years ago
FIRST TO ANSWER GETS BRAINLIEST
iVinArrow [24]

Step-by-step explanation:

3x - y = 74

4y = x

Replace x in the first expression by 4y

3x - y = 74 ➡ 3(4y) - y = 74

12y - y = 74

11y = 74

y = 74/11 we can use this to find x

4y = x

4 × 74/11 = x

296/11 = x

5 0
3 years ago
The ratio
vaieri [72.5K]
1 : 100,000
Because there are 100cm in a m and 1000m in a km
100 x 1000 = 100,000
3 0
3 years ago
A population of bacteria begins with 1500 bacteria and grows to 4500 in one hour.
dezoksy [38]

The function that represents the growth of this culture of bacteria as a function of time is; P = 1500e^(1.0986t)

<h3>How to calculate Exponential Growth?</h3>

The formula for exponential growth is;

P = P₀e^(rt)

where;

P = current population at time t

P₀ = starting population

r = rate of exponential growth/decay

t = time after start

Thus, from our question we have;

4500 = 1500 * e^(r * 1)

4500/1500 = e^r

e^r = 3

In 3 = r

r = 1.0986

Thus, the function that represents the growth of this culture of bacteria as a function of time is;

P = 1500e^(1.0986t)

For the culture to double, then;

P/P₀ = 2. Thus;

e^(1.0986t) = 2

In 2 = 1.0986t

t = 0.6931/1.0986

t = 0.631 hours

Read more about Exponential Growth at; brainly.com/question/27161222

#SPJ1

4 0
2 years ago
Can I please get help with these ASAP
Gre4nikov [31]

Answer:

Kindly find attached.

7 0
3 years ago
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