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Elan Coil [88]
3 years ago
11

What is the value for "m" that makes the equation true?

Mathematics
1 answer:
Anna11 [10]3 years ago
3 0
Hi I think the answer is 24 hope that’s right
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How does 8 4/3 = 9 1/3?​
irga5000 [103]

You're question asks why the given mixed numbers are equal.

In fact, they're equal.

Lets make it easier for you to understand:

8 4/3 has a improper fraction "4/3", that fraction is over 1 whole.

You could look at 8 4/3 as:

8 + 3/3 + 1/3

The 3/3 turns into 1:

8 + 1 + 1/3

9 + 1/3

9 1/3

You would see that it turns into 9 1/3, therefore they are equal.

7 0
3 years ago
A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate
Shkiper50 [21]

The amount of salt in the tank changes with rate according to

Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)

\implies Q'+\dfrac Q{300+3t}=4

which is a linear ODE in Q(t). Multiplying both sides by (300+3t)^{1/3} gives

(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}

so that the left side condenses into the derivative of a product,

\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}

Integrate both sides and solve for Q(t) to get

(300+3t)^{1/3}Q=(300+3t)^{4/3}+C

\implies Q(t)=300+3t+C(300+3t)^{-1/3}

Given that Q(0)=100, we find

100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}

and we get the particular solution

Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}

\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}

5 0
3 years ago
If ∠1 and ∠2 are vertical angles and m∠2 = 108°, find m∠1.
oee [108]

Answer:

angle 1 = 108°

Step-by-step explanation:

because angle 1 and angle 2 are vertical angles and vertical angles are equal.

6 0
3 years ago
A merry-go-round has a radius of 18 feet. If a passenger gets on a
sdas [7]

Answer:

121 degrees

Step-by-step explanation:

The "arc length" formula is s = rФ, where Ф represents the central angle in radians (not degrees).

Here r = 18 ft and s = 38 ft, and so:

                                     38 ft

s = rФ becomes Ф = ------------ = 2.111 radians

                                     18 ft

which, in degrees, is:

2.111 rad      180 deg

------------- * --------------- = 121 degrees, to the nearest degree

      1            3.142

4 0
3 years ago
Read 2 more answers
X^2-6x-25=0. Solve by completing the square.
Slav-nsk [51]
<span>Hey there,
x^2 -6x+25=0
Per quadratic formula, roots of ax^2+bx+c are
x=[-b+sqrt(b^2-4ac)]/2a and x=[-b-sqrt(b^2-4ac)]/2a

In this example, a=1, b=-6, and c=25
So, x= [6+sqrt(36-100)]/2 and x= [6-sqrt(36-100)]/2
=> x = [6+sqrt(-64)]/2 and x = [6-sqrt(-64)]/2 
=> x = 3+4i and x= 3-4i

Hope this helped you alot!!!!!!!!</span>
7 0
3 years ago
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