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2 years ago

8

a car is traveling at a constant velocity of 60km/h east for 4 hours. choose the correct statement about the acceleration of the

car

2 answers:

elena55 [62]2 years ago

6 0

I’m just saying this so I can get points but I think if u divide u should get da answer

Mrac [35]2 years ago

3 0

So by definition and in math talk, A = dV/dT = 0/4 = 0 acceleration. ANS. A hope that helped

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Help me I need the answer to #2 and #4

Karo-lina-s [1.5K]

Number 2 is 84.13
number 4 is 56

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3 years ago

A plane flies 510 kilometers with a bearing of 316° from Naples to Elgin (see figure). The plane then flies 720 kilometers from

IgorC [24]

Answer:

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Step-by-step explanation:

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3 years ago

Brainiest will be given . Please help me

mixas84 [53]

Answer:

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Using that formula

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Step-by-step explanation:

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2 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

<u>Given</u>:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

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3 years ago

Read 2 more answers

Let f(x)=3x+2 and g(x)=5x-8 find all value of x for which f(x) > g(x)

kirill115 [55]

Answer:

$x < 5$

Step-by-step explanation:

$f(x) > g(x) \\ < = > 3x + 2 > 5x + 2 \\ < = > - 2x > - 10 \\ < = > x < 5 \:( qed)$

4 0

3 years ago