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valentinak56 [21]
3 years ago
12

If the pOH increases is a solution getting more basic or less basic?

Chemistry
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

Increases

Explanation:

Both acids and bases can measured

using the pH or pOH scale. Both

scales provide a measure of either

the H+ concentration or the OHconcentration.

Notice that each scale shows were

acids and bases both are located.

• When acids are measured, the

pH is less than 7, but the pOH

is greater than 7.

• When bases are measured,

the pH is greater than 7, but

the pOH is less than 7.

Both scales are dependent on what

ion you are measuring

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stiks02 [169]

Answer:

0.147 billion years = 147.35 million years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
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  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
  • The half-life of Potassium-40 is 1.25 billion years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1.25 billion years) = 0.8 billion year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

<em></em>

where, k is the rate constant of the reaction (k = 0.8 billion year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of (Potassium-40) ([A₀] = 100%).

[A] is the remaining concentration of (Potassium-40) ([A] = 88.88%).

  • At the time needed to be determined:

<em>8 times as many potassium-40 atoms as argon-40 atoms. Assume the argon-40 only comes from radioactive decay.</em>

  • If we start with 100% Potassium-40:

∴ The remaining concentration of Potassium-40 ([A] = 88.88%).

and that of argon-40 produced from potassium-40 decayed = 11.11%.

  • That the ratio of (remaining Potassium-40) to (argon-40 produced from potassium-40 decayed) is (8: 1).

∴ t = (1/k) ln([A₀]/[A]) = (1/0.8 billion year⁻¹) ln(100%/88.88%) = 0.147 billion years = 147.35 million years.

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3 years ago
How many atoms are present in 48.60 g of Mg
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1.204 x 10 ( 24 ) atoms of magnesium are present.
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1. convert mass of Mg to moles of Mg using the molar mass of Mg as converted to a factor 

2. convert moles of Mg to atoms of Mg using the Avogadro's number ( 6.02 x 10  (23) as a conversion factor 
 
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Answer:

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The detailed step is shown in the attachment.

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