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valentinak56 [21]
3 years ago
12

If the pOH increases is a solution getting more basic or less basic?

Chemistry
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

Increases

Explanation:

Both acids and bases can measured

using the pH or pOH scale. Both

scales provide a measure of either

the H+ concentration or the OHconcentration.

Notice that each scale shows were

acids and bases both are located.

• When acids are measured, the

pH is less than 7, but the pOH

is greater than 7.

• When bases are measured,

the pH is greater than 7, but

the pOH is less than 7.

Both scales are dependent on what

ion you are measuring

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Answer:- 0.800 moles of the gas were collected.

Solution:- Volume, temperature and pressure is given for the gas and asks to calculate the moles of the gas.

It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:

PV=nRT

Since it asks to calculate the moles that is n, so let's rearrange this for n:

n=\frac{PV}{RT}

V = 19.4 L

T = 17 + 273 = 290 K

P = 746 mmHg

we need to convert the pressure from mmHg to atm and for this we divide by 760 since, 1 atm = 760 mmHg

P=746mmHg(\frac{1atm}{760mmHg})

P = 0.982 atm

R = 0.0821\frac{atm.L}{mol.K}

Let's plug in the values in the equation to get the moles.

n=\frac{0.982atm*19.4L}{0.0821\frac{atm.L}{mol.K}*290K}

n = 0.800 moles

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In france grapes are 1.83 euros per kilogram. What is the cost of grapes in dollars per pound if the exchange rate is 1.40 dolla
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In france grapes are 1.83 euros per kilogram. What is the cost of grapes in dollars per pound if the exchange rate is 1.40 dollars per euro

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A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
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Answer:

5.758  is the density of the metal ingot in grams per cubic centimeter.

Explanation:

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Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d =998.2 kg/m^3

1 kg = 1000 g

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998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3

Mass of water ,m'= m - M = 45.65 g -  27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

Density=\frac{Mass}{Volume}

V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' =  9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3

Density of metal = d'

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Difference in volume will give volume of metal ingot.

v' = v - V

v'=19.73 cm^3-18.08 cm^3=

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Since volume cannot be in negative .

Density of the metal =d'

=d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3

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