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Jobisdone [24]
3 years ago
6

PLS ANSWER ASAP

Physics
1 answer:
lidiya [134]3 years ago
8 0
3,728.2271 miles per hour please mark brainliest
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Imagine that a bowling ball needs to be lifted 1.5 meters, and its gravitational potential energy is 90 joules. How much does th
Vikki [24]

Answer: 6.12 kg

Explanation:

Since Mass of ball = ? (let the unknown value be Z)

Acceleration due to gravity, g= 9.8m/s^2

Height, h = 1.5 metres

Gravitational potential energy GPE = 90J

Gravitational potential energy depends on the weight of the ball, the action of gravity and height.

Thus, GPE = Mass m x Acceleration due to gravity g x Height h

90J = Z x 9.8m/s^2 x 1.5m

90 = Z x 14.7

Z = 90/14.7

Z = 6.12 kg

Thus, the bowling ball weigh 6.12 kilograms

8 0
3 years ago
Suppose Galileo dropped a lead ball (100 kilograms) and a glass ball (1 kilogram) from the Leaning Tower of Pisa. Which one hit
pogonyaev
If he dropped them both at the same time, then as close as anyone could tell, they both hit the ground at the same time.
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What is f =ma derivation?<br>​
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Derive relation F = ma from Newton 2nd Law of Motion. Let us derive the relation of force F = ma from Newton's second law: ... It means that the linear momentum will change faster when a bigger force is applied. Consider a body of mass 'm' moving with velocity v.

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3 years ago
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A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 5.00 m ab
maria [59]

Answer:

W = 0.678 rad/s  

Explanation:

Using the conservation of energy:

E_i =E_f

Roll up and hill without slipping is the sumatory of two energys, rotational and translational, so:

\frac{1}{2}IW^2+ \frac{1}{2}mV^2 = mgh

where I is the moment of inertia, W the angular velocity at the base of the hill, m the mass of the ball, V the velocity at the base of the hill, g the gravity and h the altitude.

First, we will find the moment of inertia as:

I =\frac{2}{3}mR^2

where m is the mass and R the radius, so:

I =\frac{2}{3}(0.426kg)(11.3m)^2

I = 36.26 Kg*m^2

Then, replacing values on the initial equation, we get:

\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)V^2 = (0.426kg)(9.8)(5m)

also we know that:

V =WR

so:

\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)W^2R^2 = (0.426kg)(9.8)(5m)

Finally, solving for W, we get:

W^2(\frac{1}{2}(36.26)+ \frac{1}{2}(0.426kg)(11.3m)^2) = (0.426kg)(9.8)(5m)

W = 0.678 rad/s

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3 years ago
Witch of the following best describes the forms of electromagnetic waves produced by sunlight ?
zubka84 [21]

Answer:

A: Sunlight contains ultraviolet waves only.

Explanation:

Hopefully this helps!

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