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natita [175]
3 years ago
7

What mass of HCl is needed to prepare 1.00 mole of Cl₂? 2 KMnO₄ + 16 HCl → 2MnCl₂ + 5 Cl₂ + 8 H₂O + 2 KCl

Chemistry
1 answer:
dsp733 years ago
8 0

Answer:

117 g HCl

Explanation:

use a molar ratio to cancel out the moles of Cl2

1.00 mol Cl2 x 16 mol HCl / 5 mol Cl2

multiply by the molar mass of HCl to get the mass of the HCl

3.2 mol HCl x 36.46 g HCl

then you should get around

116.672 g HCl

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Zingerone, one of the flavor molecules in ginger,
MissTica

The molecular formula of the compound is C12H15O3 hence the molar mass of the compound is 207 g/mol.

We need to obtain the number of moles of carbon, hydrogen and oxygen in the compound;

Carbon = 24.91 g/44g/mol × 1 mole of carbon = 0.566 moles

Mass of carbon =  0.566 moles × 12 g/mol = 6.792 g

Number of moles of hydrogen = 6.522 g/18 g/mol × 2 moles = 0.725 moles

Mass of hydrogen = 0.725 moles  × 1 g/mol = 0.725 g

Mass of oxygen = 10 - (6.792 g + 0.725 g) = 2.483 g

Number of moles of oxygen = 2.483 g/16 g/mol = 0.155 moles

Now we must divide through by the lowest number of moles;

C - 0.566/0.155   H - 0.725/0.155     O - 0.155/0.155

C - 4                    H - 5                        O - 1

The simplest formula is C4H5O Recall that the molar mass of the compound lies between 150.0 and 220.0 g/mol

4(12) + 5(1) + 16 = 69

Hence; n = 3 and the molecular formula of the compound is C12H15O3

The molar mass of the compound is; 12(12) + 15(1) + 3(16) = 207 g/mol

Learn more: brainly.com/question/15180604

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