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natita [175]
3 years ago
7

What mass of HCl is needed to prepare 1.00 mole of Cl₂? 2 KMnO₄ + 16 HCl → 2MnCl₂ + 5 Cl₂ + 8 H₂O + 2 KCl

Chemistry
1 answer:
dsp733 years ago
8 0

Answer:

117 g HCl

Explanation:

use a molar ratio to cancel out the moles of Cl2

1.00 mol Cl2 x 16 mol HCl / 5 mol Cl2

multiply by the molar mass of HCl to get the mass of the HCl

3.2 mol HCl x 36.46 g HCl

then you should get around

116.672 g HCl

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cestrela7 [59]
It depends on your answers. Common liquid measuring devices include Graduated Cylinders, Test Tubes, and Beakers. The most likely answer to your question would be a Graduated Cylinder.
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3 years ago
At 170C, a sample of hydrogen gas occupies 125cm3. What will be the volume at 1000C? =161cm3 If the volume of a given mass of ga
pickupchik [31]

1. V= 161

2. V = 37.3

<h3 /><h3>Further explanation  </h3>

Charles's Law states that  

<em>When the gas pressure is kept constant, the gas volume is proportional to the temperature  </em>

\tt \dfrac{V1}{T1}=\dfrac{V2}{T2}

1.

\tt \dfrac{125}{17+273.15~K}=\dfrac{V2}{100+273.15}\\\\V2=160.7\rightarrow 161~cm^3

2.

\tt \dfrac{27.3}{0+273.15`K}=\dfrac{V2}{100+273.15}\\\\V2=37.3~cm^3

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3 years ago
PLZ HELP?! 50 points <br><br> Write the correct IUPAC name for the following compound
slamgirl [31]

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2-ethly-3-5 dimethylheptam

Explanation:

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2 years ago
What is the freezing point (in degrees Celcius) of 3.75 kg of water if it contains 189.9 g of C a B r 2?
blondinia [14]

Answer:

The freezing point of the solution is -1.4°C

Explanation:

Freezing point decreases by the addition of a solute to the original solvent, <em>freezing point depression formula is:</em>

ΔT = kf×m×i

<em>Where Kf is freezing point depression constant of the solvent (1.86°C/m), m is molality of the solution (Moles CaBr₂ -solute- / kg water -solvent) and i is Van't Hoff factor.</em>

Molality of the solution is:

-moles CaBr₂ (Molar mass:

189.9g ₓ (1mol / 199.89g) = 0.95 moles

Molality is:

0.95 moles CaBr₂ / 3.75kg water = <em>0.253m</em>

Van't hoff factor represents how many moles of solute are produced after the dissolution of 1 mole of solid solute, for CaBr₂:

CaBr₂(s) → Ca²⁺ + 2Br⁻

3 moles of ions are formed from 1 mole of solid solute, Van't Hoff factor is 3.

Replacing:

ΔT = kf×m×i

ΔT = 1.86°C/m×0.253m×3

ΔT = 1.4°C

The freezing point of water decreases in 1.4°C. As freezing point of water is 0°C,

<h3>The freezing point of the solution is -1.4°C</h3>

<em />

4 0
3 years ago
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Answer:

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