Question

What mass of HCl is needed to prepare 1.00 mole of Cl₂? 2 KMnO₄ + 16 HCl → 2MnCl₂ + 5 Cl₂ + 8 H₂O + 2 KCl

Answer 1

Answer:

117 g HCl

Explanation:

use a molar ratio to cancel out the moles of Cl2

1.00 mol Cl2 x 16 mol HCl / 5 mol Cl2

multiply by the molar mass of HCl to get the mass of the HCl

3.2 mol HCl x 36.46 g HCl

then you should get around

116.672 g HCl