quizlet can help you its very helpful on quizes it some time mostly have the same excact quizes
Answer:
9.248 <
< 9.253 mm
Explanation:
Given data:
standard deviation = 0.021 mm
sample mean = 9.251 mm
total sample = 409 m
confidence interval level = 95%
mean diameter of entire batch ![\mu = \bar X \pm z \frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Cmu%20%20%3D%20%5Cbar%20X%20%5Cpm%20z%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
where
- sample mean = 9.251 mm
z = critical value
plugginf all value in the above relation to get the mean diameter
![\mu = 9.251 \pm 1.96 \times \frac{0.021}{\sqrt{409}}](https://tex.z-dn.net/?f=%5Cmu%20%3D%209.251%20%5Cpm%201.96%20%5Ctimes%20%5Cfrac%7B0.021%7D%7B%5Csqrt%7B409%7D%7D)
9.248 <
< 9.253 mm
Answer:
P > 142.5 N (→)
the motion sliding
Explanation:
Given
W = 959 N
μs = 0.3
If we apply
∑ Fy = 0 (+↑)
Ay + By = W
If Ay = By
2*By = W
By = W / 2
By = 950 N / 2
By = 475 N (↑)
Then we can get F (the force of friction) as follows
F = μs*N = μs*By
F = 0.3*475 N
F = 142.5 N (←)
we can apply
P - F > 0
P > 142.5 N (→)
the motion sliding
<h2>
Corrected Question:</h2>
A step-up transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of 4100 V with a 16-mA current, what input current and voltage are needed?
<h2>
Answer:</h2>
The input current and voltage needed are 443 mA and 148 V respectively.
<h2>
Explanation:</h2>
In a step-up transformer, the relationship between the number of turns in its primary coil (
), the number of turns in its secondary coil (
), the input voltage (
), the output voltage (
), the input current (
), and the output current (
) is given by;
=
=
This implies that;
=
---------------------(i)
=
---------------------(ii)
From the question;
= 26 turns
= 720 turns
= 4100V
= 16mA = 16 x 10⁻³A
(a) Substitute these values into equation (ii) as follows;
= ![\frac{I_{p} }{16*10^{-3}}](https://tex.z-dn.net/?f=%5Cfrac%7BI_%7Bp%7D%20%7D%7B16%2A10%5E%7B-3%7D%7D)
Solve for
;
= 720 x 16 x 10⁻³ / 26
= 443 x 10⁻³
= 443 mA
Therefore the input current needed is 443mA
(b) Also, substitute those values into equation (i) as follows;
= ![\frac{4100 }{V_{p} }](https://tex.z-dn.net/?f=%5Cfrac%7B4100%20%7D%7BV_%7Bp%7D%20%7D)
Solve for
;
= 4100 x 26 / 720
= 148 V
Therefore, the input current needed is 148 V
Answer:
F = 2840.3 N
Explanation:
Given:
- Diameter of window D = 0.3 m
- Midpoint of window from sea level h = 4 m
- Specific gravity of sea water S.G = 1.024
- Density of water p = 1000 kg/m^3
Find:
The hydro-static force F_r acting on the mid-point of the window.
Solution:
- The average pressure P acting on the midpoint of the window:
P = S.G p*g*h
P = 1.024*1000*9.81*4
P = 40181.76
- The hydro-static force F_r acting on the mid-point of the window:
F = P*A = P*pi*D^2 / 4
F = 40181.76*pi*0.3^2 / 4
F = 2840.3 N