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stiv31 [10]
3 years ago
10

Complex poles cmd zeros. Sketch the asymptotes of the Bode plot magnitude and phase for each of the listed open-loop mmsfer fuoc

tions. and approximate the transitillll at the stX'ond-order break point. based on the value of the ... ,. ,, 410. The Frequency-Response Design Method damping ratio. After completing the hand sketches, verify your result using Mallab. Tum in your hand sketches and the Matlab results on the same scales.
(a) L(s) = s2 + 3~r + 10
(b) L(s) = s(s2 + ~s + 10)
(c) L(s) = (s2 + 2s + 8) s(s2 + 2s + 10)
(d) L(s) = (s2 +I) s(s• +4)
(e) L(s) = (s:? +4) s(.r~ + I) 6
Engineering
1 answer:
Roman55 [17]3 years ago
8 0

Answer: e is the best answer

Explanation:

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A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of
andrew-mc [135]

Answer:

The correct answer is "1341.288 W/m".

Explanation:

Given that:

T₁ = 300 K

T₂ = 500 K

Diameter,

d = 0.2 m

Length,

l = 1 m

As we know,

The shape factor will be:

⇒ SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}

By putting the value, we get

⇒       =\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}

⇒       =3.7258 \ l

hence,

The heat loss will be:

⇒ Q=SF\times K(T_2-T_1)

       =3.7258\times 1\times 1.8\times (500-300)

       =3.7258\times 1.8\times (200)

       =1341.288 \ W/m

3 0
3 years ago
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