Answer:
The answer is C.
Step-by-step explanation:
You have to square both sides :
Then, you have to simplify it :
Expanded form pretty much means that you break down every digit into an addition phrase. So, for 418,832, that would mean:
4 1 8 8 3 2
400000 10000 8000 800 30 2
400000+10000+8000+800+30+2
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Step-by-step explanation:
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Answer:
Step-by-step explanation:
We have been given that there are total 9 people who entered the drawing competition. There are 3 prizes to be distributed to the winners. The total number of ways that 3 prizes can be awarded to the 9 people can be determined as 9*8*7 = 504.
The total number of ways in which I win the first prize and my mom wins the second prize would be 1*1*7 = 7.
Therefore, the probability that I win the first prize and my mom wins the second prize would be: 
