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3 years ago

Are there instances that rational algebraic equation can be transformed into quadratic equation

Mathematics

2 answers:

NemiM [27]3 years ago

5 0

Answer:

yes you can

Step-by-step explanation:

for example you have a second order algebraic equation, which have the general form ax^2 + bx + c = 0, for any constants a, b, and c, you can use the quadratic equation to find the values of x. However, sometimes it is easier to simply factor the expression into (fx+g)(hx+i) = 0, for any constants f, g, h, and i, and then solve the two resulting equations fx+g = 0 and hx+i=0 for the values of x.

i hope this helps

eimsori [14]3 years ago

4 0

Answer:

yeah

Step-by-step explanation:

hmm

You might be interested in

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago

Please help! The answer isn’t 36! <br> Find the value of the expression:

Brums [2.3K]

Answer:

3.6

Step-by-step explanation:

Hi there!

We are given this expression:

.6√36 (.6*√36)

And we want to find the value of it

.6 can be re-written as 0.6

In that case,

0.6*√36

First, simplify what's under the radical: √36, which is equal to 6 (6*6=36)

The expression then becomes:

0.6*6

Multiply those numbers together

0.6*6=<u>3.6</u>

Hope this helps!

8 0

2 years ago

The heights of North American women are normally distributed with a mean of 64 inches and a standard deviation of 2inches.a. Wha

Charra [1.4K]

Answer:

a) $P(X>66)=P(Z>1)=1-P(Z$

b) $P(\bar X >66)=P(Z>2)=1-P(Z$

c) $P(\bar X >66)=P(Z>10)=1-P(Z$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(64,2)$