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2 years ago

How much force is required to stretch a spring 12 cm, if the spring constant is 55 N/m?

Physics

1 answer:

Reika [66]2 years ago

7 0

Answer:

Explanation:

F = -kΔx

Since the spring constant is given in N/m, we need to convert the stretch to meters as well.

12 cm = .12 m

Now we can solve the problem:]

F = -55(-.12) so

F = 6.6N

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2 years ago

A spaceship whose rest length is 350m has a speed of .82c

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Answer:

$t'=1.1897*10^{-6} s$

t'=1.1897 μs

Explanation:

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Formula:

$u=\frac{u'+v}{1+\frac{u'*v}{c^{2}}}$

where:

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In order to find u' , we can rewrite the above expression as:

$u'=\frac{v-u}{\frac{u*v}{c^{2} }-1 }$

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u'=0.9806c

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$t'=\frac{350}{0.9806c}$ (c = 3*10^8 m/s)

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t'=1.1897 μs

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3 years ago

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2 years ago

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Answer:

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